爲什麼我得到錯誤錯誤C2664： 'reverseString'

Question

#include <iostream> 
#include <string> 
#include <iomanip> 

using namespace std; 

typedef char string80[81];  // create a synonym for another type 
void reverseString(string80);  // function prototype 
int main() 
{    
    // start program compilation here 
    char string80, name;   // variable to contain the name of the user 

    cout << "Enter your name =====> " ; 
    cin >> name,81; 

    cout << "\n\nWelcome to Computer Science 1106 " << name << endl<< endl; 

    reverseString(name); 

    cout << "Your name spelled backwards is " << name << endl << endl; 

    return 0; 
} // end function main 
    // Function to reverse a string 
    // Pre: A string of size <= 80 Post: String is reversed 

void reverseString(string80 x) 
{ 
    int last = strlen(x)- 1; // location of last character in the string 
    int first = 0;  // location of first character in the string 
    char temp; 

    // need a temporary variable 
    while(first <= last) 
    { // continue until last > first 

    temp = x[first];  // Exchange the first and last characters 
    x[first] = x[last];   
    x[last] = temp; 
    first++;  // Move on to the next character in the string 
    last--;    // Decrement to the next to last character in the string 
    }// end while 
}// end reverseString 

我得到一個錯誤

C2664： 'reverseString'：無法從 '字符' 轉換參數1至 '的char []' 轉換，從整型到指針類型需要 的reinterpret_cast，C樣式轉換或函數樣式轉換

Answer 1

的reverseString函數接受char [81]爲x參數尚未你發送一個char當你叫它。

什麼你可能想要做的是申報string80和name作爲char [81]而不是char

char string80[81], name[81]; 

Answer 2

您聲明name爲char型的，當它應該輸入爲string80（從你的typedef） 。

您還通過聲明char string80意外隱藏了您的typedef，它隱藏了來自周圍範圍的typedef。

你想聲明name類型string80，而不是char類型。類似這樣的：

string80 name;