0
我已經使用下面的代碼來運行兩個不同的依賴下拉列表。細分取決於區和衣服取決於性別。它不工作。哪裏有問題?我們可以使用這樣的兩個功能嗎?使用jquery的多個依賴下拉列表
$(function(){
var $cat = $("#cat"),
$subcat = $("#subcat");
$cat.on("change",function(){
var _rel = $(this).val();
$subcat.find("option").attr("style","");
$subcat.val("");
if(!_rel) return $subcat.prop("disabled",true);
$subcat.find("[rel="+_rel+"]").show();
$subcat.prop("disabled",false);
});
var $cat1 = $("#cat1"),
$subcat1 = $("#subcat1");
$cat1.on("change",function(){
var _rel = $(this).val();
$subcat1.find("option").attr("style","");
$subcat1.val("");
if(!_rel) return $subcat1.prop("disabled",true);
$subcat1.find("[rel="+_rel+"]").show();
$subcat1.prop("disabled",false);
});
});
District: <select name="dis" id="cat" required><option></option><option
>North </option><option >Unakoti</option></select>
Subdivision: <select name="subd" id="subcat" required><option></option>
<option rel="North" value="Dharmanagar">Dharmanagar</option>
<option rel="North" value="Panisagar">Panisagar</option>
<option rel="North" value="Kanchanpur">Kanchanpur</option>
<option rel="Unakoti" value="Kailasahar">Kailasahar</option>
<option rel="Unakoti" value="Kumarghat" >Kumarghat</option></select>
Gender: <select name="gen" id="cat1" required><option></option><option >M
</option><option >F</option></select>
Dress: <select name="dre" id="subcat1" required><option></option>
<option rel="M" value="D1">D1</option>
<option rel="M" value="D2">D2</option>
<option rel="M" value="D3">D3</option>
<option rel="F" value="D4">D4</option>
<option rel="F" value="D5" >D5</option>
</select>
我編輯了我的代碼。但仍然不起作用 –
問題解決了,這是一個愚蠢的錯誤。 –