您可以從類找到它NTRUEncryptionKeyPairGenerator
public AsymmetricCipherKeyPair generateKeyPair()
{
int N = params.N;
int q = params.q;
int df = params.df;
int df1 = params.df1;
int df2 = params.df2;
int df3 = params.df3;
int dg = params.dg;
boolean fastFp = params.fastFp;
boolean sparse = params.sparse;
Polynomial t;
IntegerPolynomial fq;
IntegerPolynomial fp = null;
// choose a random f that is invertible mod 3 and q
while (true)
{
IntegerPolynomial f;
// choose random t, calculate f and fp
if (fastFp)
{
// if fastFp=true, f is always invertible mod 3
t = params.polyType == NTRUParameters.TERNARY_POLYNOMIAL_TYPE_SIMPLE ? Util.generateRandomTernary(N, df, df, sparse, params.getRandom()) : ProductFormPolynomial.generateRandom(N, df1, df2, df3, df3, params.getRandom());
f = t.toIntegerPolynomial();
f.mult(3);
f.coeffs[0] += 1;
}
else
{
t = params.polyType == NTRUParameters.TERNARY_POLYNOMIAL_TYPE_SIMPLE ? Util.generateRandomTernary(N, df, df - 1, sparse, params.getRandom()) : ProductFormPolynomial.generateRandom(N, df1, df2, df3, df3 - 1, params.getRandom());
f = t.toIntegerPolynomial();
fp = f.invertF3();
if (fp == null)
{
continue;
}
}
fq = f.invertFq(q);
if (fq == null)
{
continue;
}
break;
}
// if fastFp=true, fp=1
if (fastFp)
{
fp = new IntegerPolynomial(N);
fp.coeffs[0] = 1;
}
// choose a random g that is invertible mod q
DenseTernaryPolynomial g;
while (true)
{
g = DenseTernaryPolynomial.generateRandom(N, dg, dg - 1, params.getRandom());
if (g.invertFq(q) != null)
{
break;
}
}
IntegerPolynomial h = g.mult(fq, q);
h.mult3(q);
h.ensurePositive(q);
g.clear();
fq.clear();
NTRUEncryptionPrivateKeyParameters priv = new NTRUEncryptionPrivateKeyParameters(h, t, fp, params.getEncryptionParameters());
NTRUEncryptionPublicKeyParameters pub = new NTRUEncryptionPublicKeyParameters(h, params.getEncryptionParameters());
return new AsymmetricCipherKeyPair(pub, priv);
}
f爲你以後的多項式。 你是什麼意思的基礎? 幾乎逆和快速NTRU密鑰創建
https://www.securityinnovation.com/uploads/Crypto/NTRUTech014.pdf
它是通過以下幾個步驟做了優化的F
發現逆:
逆方法在NTRU報告014描述Z/2Z /(x^N-1)
將其擡升至Z/2^rZ /(x^N-1)
重複至2^r = q