2012-11-28 106 views
0

我有一個php頁面的上傳表單,將csv文件放入數據庫。未能打開流:沒有這樣的文件或目錄PHP

我在提交我的csv文件中得到一個錯誤:

Warning: move_uploaded_file(/public_html/csv/test/books.csv) [function.move-uploaded-file]: failed to open stream: No such file or directory in /home/blakeloi/public_html/csv/index.php on line 19 

Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move '/tmp/phpZw2e2X' to '/public_html/csv/test/books.csv' in /home/blakeloi/public_html/csv/index.php on line 19 

這是錯行:

$upload_path = '/Users/blakeloizides/Desktop'; 

在:

if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) 

我有嘗試重命名我的文件路徑多次,並沒有什麼似乎工作。最明顯的答案是,我的文件目錄路徑是錯誤的,但我把文件夾放到我的瀏覽器中,得到了正確的路徑。我甚至試圖在我的server/public_html/test上使用一個文件夾,但這不起作用。

<?php 

$message = null; 

$allowed_extensions = array('csv'); 

$upload_path = '/Users/blakeloizides/Desktop'; 

if (!empty($_FILES['file'])) { 

if ($_FILES['file']['error'] == 0) { 

    // check extension 
    $file = explode(".", $_FILES['file']['name']); 
    $extension = array_pop($file); 

    if (in_array($extension, $allowed_extensions)) { 

     if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) { 

      if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) { 

       $keys = array(); 
       $out = array(); 

       $insert = array(); 

       $line = 1; 

       while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) { 

        foreach($row as $key => $value) { 
         if ($line === 1) { 
          $keys[$key] = $value; 
         } else { 
          $out[$line][$key] = $value; 

         } 
        } 

        $line++; 

       } 

       fclose($handle);  

       if (!empty($keys) && !empty($out)) { 

        $db = new PDO('mysql:host=localhost;dbname=blakeloi_import-csv', 'blakeloi_root', 'password'); 
        $db->exec("SET CHARACTER SET utf8"); 

        foreach($out as $key => $value) { 

         $sql = "INSERT INTO `books` (`"; 
         $sql .= implode("`, `", $keys); 
         $sql .= "`) VALUES ("; 
         $sql .= implode(", ", array_fill(0, count($keys), "?")); 
         $sql .= ")"; 
         $statement = $db->prepare($sql); 
         $statement->execute($value); 

        } 

        $message = '<span class="green">File has been uploaded successfully</span>'; 

       } 

      } 

     } 

    }  else { 
     $message = '<span class="red">Only .csv file format is allowed</span>'; 
    } 

} else { 
    $message = '<span class="red">There was a problem with your file</span>'; 
} 

} 

?> 
    <!DOCTYPE HTML> 
    <html lang="en"> 
    <head> 
<meta charset="utf-8" /> 
<title>Upload CSV to MySQL</title> 
<meta name="description" content="" /> 
<meta name="keywords" content="" /> 
<link href="css/core.css" rel="stylesheet" type="text/css" /> 
<!--[if lt IE 9]> 
<script src="http://html5shiv.googlecode.com/svn/trunk/html5.js"></script> 
<![endif]--> 
</head> 
<body> 

<section id="wrapper"> 

<form action="" method="post" enctype="multipart/form-data"> 

    <table cellpadding="0" cellspacing="0" border="0" class="table"> 
     <tr> 
      <th><label for="file">Select file</label> <?php echo $message; ?></th> 
     </tr> 
     <tr> 
      <td><input type="file" name="file" id="file" size="30" /></td> 
     </tr> 
     <tr> 
      <td><input type="submit" id="btn" class="fl_l" value="Submit" /></td> 
     </tr> 
    </table> 

</form> 

</section> 

</body> 
</html> 

enter image description here

我的index.php文件是坐在的public_html/CSV或http://www.blakeloizides.co.za/csv ,我要上傳的文件的public_html/CSV /測試或http://www.blakeloizides.co.za/csv/test

我的權限是755兩個文件夾。

enter image description here

+0

您是否檢查了上傳文件夾的權限? – amburnside

+0

經常遇到此錯誤,並快速排除故障,請按照下列步驟操作:https://stackoverflow.com/a/36577021/2873507 –

回答

0

我不得不改變我的文件路徑爲/ home/blakeloi /的public_html/CSV /測試。那是我使用的錯誤/ public_html/csv/test

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