Google圖表錯誤

Question

當試圖使用Google圖表代碼繪製折線圖時，我收到此錯誤

錯誤：類型不匹配。值0.8與列索引中的類型編號不匹配0

'0.8'是指代碼中的值p1。

function drawChart() { 

// Create the data table. 
var data = new google.visualization.DataTable(); 
data.addColumn('number', 'Topping'); 
data.addColumn('number', 'Slices'); 
data.addRows([ 
    [p1,1.89], 
[ch_period[17],5], 
[3,2], 
[5,2], 
[5,2], 
[6,7] 
]); 

// Set chart options 
var options = {'title':'How Much Pizza I Ate Last Night', 
      'width':400, 
      'height':300}; 

// Instantiate and draw our chart, passing in some options. 
var chart = new google.visualization.LineChart(document.getElementById('chart_div')); 
chart.draw(data, options); 

Answer 1

我做你的代碼的jsfiddle的作品：http://jsfiddle.net/kychan/Dfx4V/1/

var p1  = parseInt('4'), 
    ch_period = {'17':4}; 

function drawChart() { 

    // Create the data table. 
    var data = new google.visualization.DataTable(); 
    data.addColumn('number', 'Topping'); 
    data.addColumn('number', 'Slices'); 
    data.addRows([ 
     [p1, 1.89], 
     [ch_period[17], 5], 
     [3, 2], 
     [5, 2], 
     [5, 2], 
     [6, 7] 
    ]); 

    // Set chart options 
    var options = { 
     'title': 'How Much Pizza I Ate Last Night', 
      'width': 400, 
      'height': 300 
    }; 

    // Instantiate and draw our chart, passing in some options. 
    var chart = new google.visualization.LineChart(document.getElementById('chart_div')); 
    chart.draw(data, options); 
} 


drawChart(); 

問題是p1（也許ch_period）不是類型number。因此，您必須使用parseInt（p1）/ parseInt（ch_period）將其作爲數字，或手動將其分配給一個數字。