如何從另一個蜱

Question

減去蜱這是我得到：

獲取從會話

var markStored = PPSession.TimingMarks["loginstart"]; 

GET蜱從utcnow

var markNow = PPSession.TimingMarks["loginstart"] 
    = new TimingMark { endTime = DateTime.UtcNow.Ticks }; 

定時手柄loginstart而想要減來自儲存蜱的電流

diff = markStored - markNow; 

Answer 1

有你的最後一行的幾個問題：

1. 所有markNow首先是TimingMark所以，除非你已覆蓋了-運營商應指定哪些財產是你想用來做了一個-操作（否則就等於是說object - object）
2. 同上 - 也爲你markStored你應該指定的時間屬性格式，要在其中做-

所以：

var diff = markStored.timeField.Ticks - markNow.endTime; 

並與存根數據：

var markStored = new { Time = DateTime.Now }; 
var markNow = new { endTime = DateTime.UtcNow.Ticks }; 
var diff = markStored.Time.Ticks - markNow.endTime;