django getlist（）from ajax html form

Question

我試圖發送我的序列化表單數據到Django它應該存儲在「mylist」列表「[視頻，音頻]」。無論我在表單上檢查什麼框，views.py都會返回0。

HTML表單

<form id="myform" method="POST"> 
<input type="checkbox" name="list" value="audio"/> Audio<br /> 
<input type="checkbox" name="list" value="video"/> Video<br /> 
<input type="submit" value="Get Custom Library!" /> 
</form> 

jQuery的AJAX

<script language="JavaScript"> 
$(document).ready(function() { 
$("#myform").submit(function() { 

     $.ajax({ 
     type: "POST", 
     url: 'django/builder/buildit', 
     data: $(this).serialize(), 
     success: function(response){ 
      alert(response); 
     } 
    }); 
    return false; 
}); 
}); 
</script> 

views.py

from django.http import HttpResponse 
def main(request): 
    mylist = request.POST.getlist('list') 
    message = 0 
    for item in mylist: 
    if item == 'video': 
     message = 'vid' 
    elif item == 'audio': 
     message = 'aud' 
    return HttpResponse(message) 

Answer 1

你不給一個鍵值對的data說法，但你不應該」甚至不得不走得那麼遠 - 你不必自己收集複選框的值。使用serialize

var myCheckboxes = new Array(); 
    $("input:checked").each(function() { 
     myCheckboxes.push($(this).val()); 
    }); 

    $.ajax({ 
     type: "POST", 
     url: 'django/builder/buildit', 
     data: myCheckboxes, 
     success: function(response){ 
      alert(response); 
     } 
    }); 

有了這個，：您可以更換該

$.ajax({ 
     type: "POST", 
     url: 'django/builder/buildit', 
     data: $('#myform').serialize(), 
     success: function(response){ 
      alert(response); 
     } 
    });