tweepy新追隨者自動直接消息

Question

新的海報在這裏，所以原諒我，如果這已被覆蓋。我正在嘗試在Python中編寫一個小腳本，這將允許我自動化我的Twitter帳戶並直接傳遞新的追隨者信息。大部分代碼都可以工作，但是在嘗試實現直接消息功能時遇到了一些錯誤代碼。

這裏是我的代碼 -

 #!C:\Python27\python.exe 

import tweepy 
import webbrowser 


# Make constants to hold values of our keys 
CONSUMER_KEY = "xxxxxx" 
CONSUMER_SECRET = "xxxxxxx" 
ACCESS_TOKEN = "xxxxxxxxxx" 
ACCESS_SECRET = "xxxxxxxxxx" 


# set auth variables 
auth = tweepy.OAuthHandler(CONSUMER_KEY, CONSUMER_SECRET) 
auth.set_access_token(ACCESS_TOKEN, ACCESS_SECRET) 


# create a new api 
api = tweepy.API(auth) 


# create an instance of the twitter api class 
auth = tweepy.OAuthHandler(CONSUMER_KEY, CONSUMER_SECRET) 
auth_url = auth.get_authorization_url() 


# open the window for authorization, twitter will generate the pin 
webbrowser.open(auth_url) 
print "Copy PIN from the window that opens" 


# get the pin number from the user 
verifier = raw_input('PIN: ').strip() 
auth.get_access_token(verifier) 


# get the access key and secret returned from twitter 
access_key = auth.access_token.key 
access_secret = auth.access_token.secret 


# set authorization token 
auth.set_access_token(access_key, access_secret) 
api = tweepy.API(auth) 


# make a tweet 
def send_tweet(): 
    to_tweet = True 
    tweet_text = raw_input("Enter your tweet content below... Only the first 140 characters will be used.\n>>> ") 
    api.update_status(tweet_text[0:140]) 
    print "You tweeted \n'" + tweet_text[0:140] + "'" 
    restart = raw_input("Do you want to tweet again? (Y/N)\n>>> ") 
    if restart.lower() == "y": 
     send_tweet() 
    else: 
     print "Returning to the Main Menu...\n" 


# search twitter 
def keyword_follow(): 
    search_phrase = raw_input("What do you want to search for?\n>>> ").strip() 
    search_number = raw_input("How many results do you want to return?\n>>> ") 
    search_result = api.search(search_phrase, rpp=search_number) 
    for i in search_result: 
     print i.from_user + " said " + i.text + "\n" 
     to_follow = raw_input("Do you want to follow " + i.from_user + "? (Y/N)\n>>> ") 
     if to_follow.lower() == "n": 
      print i.from_user + " was not followed!" 
     else: 
      api.create_friendship(i.from_user) 
      print "You followed " + i.from_user + "!\n" 

    # check if the user wants to search again 
    restart = raw_input("Do you want to search again? (Y/N)\n>>> ") 
    if restart.lower() == "n": 
     print "Returning to the Main Menu...\n" 
    else: 
     return keyword_follow() 

def keyword_retweet(): 
    search_phrase = raw_input("What do you want to search for?\n>>> ").strip() 
    search_number = raw_input("How many results do you want to return?\n>>> ") 
    search_result = api.search(search_phrase, rpp=search_number) 
    for i in search_result: 
     print i.from_user + " said " + i.text + "\n" 
     to_retweet = raw_input("Do you want to retweet" + i.from_user + "? (Y/N)\n>>> ") 
     if to_retweet.lower() == "n": 
      print i.from_user + " was not retweeted!" 
     else: 
      api.retweet(i.id) 
      print "Retweeted!\n" 
      again = raw_input("See more? (Y/N)\n>>> ") 
      if again.lower() == "n": 
       break  
    # check if the user wants to search again 
    restart = raw_input("Do you want to search again? (Y/N)\n>>> ") 
    if restart.lower() == "n": 
     print "Returning to the Main Menu...\n" 
    else: 
     return keyword_retweet() 



def mass_unfollow(): 
    hits_left = api.rate_limit_status()['remaining_hits'] 
    print "You can unfollow " + str(hits_left) + " people this hour...\n" 
    print "Checking who doesn't follow you back. This will take a minute.\n" 
    # first, create some lists to hold the followers 
    followers = [] 
    friends = [] 

    # we have to use a Cursor for pagination purposes 
    for follower in tweepy.Cursor(api.followers).items(): 
     followers.append(follower) 


    for friend in tweepy.Cursor(api.friends).items(): 
     friends.append(friend) 

    # create a non_reciprocals list, these are non-followers (set - set) 
    non_reciprocal = list(set(friends) - set(followers)) 
    print str(len(non_reciprocal)) + " non-reciprocal followers.\n" 


    # first, double check that we want to unfollow 
    double_check = raw_input("Unfollow them? (Y/N) ***WARNING, THIS ACTION CANNOT BE UNDONE***\n>>> ") 


    if double_check.lower() == "y": 
     # count the number of people we unfollow, just for fun 
     counter = 0 
     for i in non_reciprocal: 
      if hits_left > 0: 
       api.destroy_friendship(i.screen_name) 
       print "Successfully unfollowed " + i.screen_name 
       hits_left -= 1 
      else: 
       print "You ran out of hits! Try again in an hour!" 

      counter += 1 
     print "You unfollowed " + str(counter) + " people!\n" 
     print "Now returning to the Main Menu." 
    else: 
     print "Returning to the Main Menu...\n" 

     #todo - automatically DM new followers  
def direct_messages(): 
    new_followers = API.followers(user) 

    for i in new_followers: 
     newDM = raw_input (i.from_user + "send follower DM?" + "Y/N") 
     if newDM.lower() == "n": 
      print i.from_user + " was not messaged" 
      print "Now returning to the Main Menu." 
    else: 
     api.send_direct_message(user_id = i.from_user, text = "message text here" 
     print "You messaged " + i.from_user 


# create the menu 
keep_running = True 
while keep_running: 
    print "Main Menu" 
    print "---------\n" 
    selection = raw_input("(1)Tweet | (2)Keyword Follow | (3)Keyword Retweet | (4)Mass Unfollow | (5)End | (6)Direct Message\n\n>>> ") 
    if selection == "1": 
     print "New Tweet" 
     print "---------\n" 
     send_tweet() 
    elif selection == "2": 
     print "Keyword Follow" 
     print "--------------\n" 
     keyword_follow() 
    elif selection == "3": 
     print "Keyword Retweet" 
     print "---------------\n" 
     keyword_retweet() 
    elif selection == "4": 
     print "Mass Unfollow" 
     print "-------------\n" 
     print "WARNING: MASS UNFOLLOW IS AGAINST THE TOS OF TWITTER. YOU'VE BEEN WARNED\n" 
     mass_unfollow() 
    elif selection == "5": 
     print "Direct Message" 
     print "------------\n" 
     direct_messages() 
    else: 
     print "BYE!\n\n" 
keep_running = False 

我處行159聲明的語法錯誤，打印，當這種打印功能被去除得到的第一個錯誤我是他們的行163得到一個錯誤，指出keep_running函數語法無效。

我是這個新手，所以它可以是我俯瞰的東西非常簡單。

任何幫助，將不勝感激

Answer 1

你缺少一個)在行158在此行中：

else: 
    api.send_direct_message(user_id = i.from_user, text = "message text here" <=== 
    print "You messaged " + i.from_user