SQL - 作爲子查詢的結果添加一列？ SQL Server 2008的

Question

我有一個查詢這給了我非常好的結果：

select 
    A.ID_acc, A.ID_us, A.st, table3.KFL, 
    '100' as myattribute, 
    '101' as my attribute2 
from 
    SOURCE1 as A 
left join 
    (select 
     table2.ID_us, table2.ID_acc, 
     CASE WHEN table2.KFL_type = 'KFL' THEN P.index_num ELSE table2.KFL_type END as KFL 
    from 
     (select 
       table1.ID_us, table1.ID_acc, 
       CASE WHEN sum(table1.count_kfl) > 1 THEN '9999' WHEN sum(table1.count_kfl) = 1 THEN 'KFL' END as KFL_type 
     from 
      (SELECT 
        ID_us, ID_acc, count(*) as count_kfl 
       FROM 
        payments 
       WHERE 
        index_num IN (200, 201, 203) 
        AND (date >= XXXX or date2 >= 'XXXXX') 
       GROUP BY 
        1, 2) as table1 
     group by 
      1, 2) as table2 
    join 
     SOURCE2 as P on table2.ID_us = P.ID_us 
         and table2.ID_acc = P.ID_acc 
    where 
     (P.date>= XXXX or P.date2 >= 'XXXXX') 
     and index_num in (201,201,203) 
    group by 
     1, 2 
    order by 
     1, 2) as table3 on table3.ID_us = A.ID_us 
         and table3.ID_acc = A.ID_acc 
where 
    A.not_deleted >= XXXXXX 

這個查詢是不是我的主要問題，所以我只有它複製只是短暫短暫，但我不知道我怎麼能現在就加一個更多的附加列（計數操作的結果）作爲我的第一個查詢結束？只是不要單獨製作2，然後混合結果。當然，我不想影響我早期的領域結果。

我有一個看起來像這樣第二個查詢：

select A.ID_us, count(*)/2 as number 
from 
SOURCE1 as A 
left join 
SOURCE3 as B 
on A.ID_acc = B.ID_acc 
where A.date >= XXXX 
group by 1 

的2個查詢之間的聯繫是其中出現在第一和第二中查詢源的屬性ID_acc。

但是不知道它是如何做到的？

select A.ID_acc, A.ID_us, A.st, table3.KFL, '100' as myattribute, '101' as my attribute2, NEWSOURCE.MYNEW_attribute 
from SOURCE1 as A 
left join 
(
... 
) 
as table3 on table3.ID_us = A.ID_us and table3.ID_acc = A.ID_acc 
where A.not_deleted >= XXXXXX 
left join 
(
. 
. 
. 
) 
as NEWSOURCE 

像這樣的事情，當然，不工作：///

Answer 1

您已經嘗試了相關子查詢：

select A.ID_acc, A.ID_us, A.st, table3.KFL, '100' as myattribute, 
'101' as my attribute2, 
(select count(*)/2 as number from SOURCE1 as IA left join SOURCE3 as IB on 
    IA.ID_acc = IB.ID_acc and IA.ID_Acc = A.ID_Acc where IA.date >= XXXX) as NewColumn 
from ... 

注意，在相關子查詢使用新的別名。