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我想讓所有按喜好數排序的電影(即使他們沒有喜歡)。我有以下工作SQL語句:活動記錄查詢接口。 Count,Join&Group
SELECT *, COUNT(case when movie_votes.like = 1 then 1 end) AS count_likes
FROM movies
LEFT OUTER JOIN movie_votes
ON movie_votes.movie_id = movies.id
GROUP BY movie_id
ORDER BY count_likes;
而我想在我的控制器中實現它。到目前爲止,我有:
Movie.select("*, COUNT(case when 'movie_votes'.'like'=1 then 1 end) AS count_likes").joins("LEFT OUTER JOIN 'movie_votes' ON 'movies'.'id'='movie_votes'.'movie_id'").group("'movie_id'")
,輸出形式控制檯:
SELECT *, COUNT(case when 'movie_votes'.'like'=1 then 1 end AS count_likes FROM `movies` LEFT OUTER JOIN 'movie_votes' ON 'movie'.'id'='movie_votes'.'movie_id' GROUP BY 'movie_id'
和Mysql2 ::錯誤:你在你的SQL語法錯誤; 我做錯了什麼沒有語法?
結束括號後失蹤 – radar 2014-09-23 12:07:10
感謝Rajesh!但我仍然在犯錯誤.. – gematzab 2014-09-23 12:30:10
你能分享電影和movie_votes的模式嗎? – 2014-09-25 09:41:08