如何在由Hibernate生成的DAO中插入@PersistenceContext 3-maven-plugin

Question

我想創建一個基於的Java應用程序Hibernate-3和Spring Framework。爲了簡化流程，我發現hibernate3-maven-plugin能夠對現有數據庫執行反向工程。
這裏有例如POM的：

<plugin> 
    <groupId>org.codehaus.mojo</groupId> 
    <artifactId>hibernate3-maven-plugin</artifactId> 
    <version>2.2</version> 
    <configuration> 
     <components> 
      <component> 
       <name>hbm2java</name> 
       <outputDirectory>src/main/java</outputDirectory> 
       <implementation>jdbcconfiguration</implementation> 
      </component> 
      <component> 
       <name>hbm2dao</name> 
       <outputDirectory>src/main/java</outputDirectory> 
       <implementation>jdbcconfiguration</implementation> 
      </component> 
     </components> 
     <componentProperties> 
      <revengfile>/src/main/resources/model.reveng.xml</revengfile> 
      <propertyfile>/src/main/resources/hibernate.properties</propertyfile> 
      <jdk5>true</jdk5> 
      <ejb3>true</ejb3> 
     </componentProperties> 
    </configuration> 
    <dependencies> 
     <dependency> 
      <groupId>mysql</groupId> 
      <artifactId>mysql-connector-java</artifactId> 
      <version>5.1.18</version> 
     </dependency> 
     <dependency> 
      <groupId>cglib</groupId> 
      <artifactId>cglib-nodep</artifactId> 
      <version>2.1_3</version> 
     </dependency> 
    </dependencies> 
    <executions> 
     <execution> 
      <phase>compile</phase> 
      <goals> 
       <goal>hbm2java</goal> 
       <goal>hbm2dao</goal> 
      </goals> 
     </execution> 
    </executions> 
</plugin> 

然後，我建立在Spring上下文：

<?xml version="1.0" encoding="UTF-8"?> 
    <beans xmlns="http://www.springframework.org/schema/beans" 
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
      xsi:schemaLocation="http://www.springframework.org/schema/beans 
      http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> 

     <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> 
      <property name="persistenceUnitName" value="gomer" /> 
     </bean> 

     <bean id="entityManager" factory-bean="entityManagerFactory" factory-method="createEntityManager"/> 

     <bean id="user" class="ru.tomtrix.first.db.UserHome"> 
      <property name="entityManager" ref="entityManager"/> 
     </bean> 
    </beans> 

它完美地生成一個實體文件，除了以下一個DAO文件。在DAO文件中有一個EntityManager：

@Stateless 
public class UserHome { 

    private static final Log log = LogFactory.getLog(UserHome.class); 

    @PersistenceContext private EntityManager entityManager; 

...並且該字段沒有setter！最終Spring拋出異常：

Invalid property 'entityManager' of bean class [ru.tomtrix.first.db.UserHome]: Bean property 'entityManager' is not writable or has an invalid setter method. Does the parameter type of the setter match the return type of the getter? 

當然，手動編寫setter並不是一個好習慣。我認爲有一種方法可以正確地注入經理。 那麼如何做到這一點，而不重寫生成的文件？

通訊信息：
1）我想創建一個獨立的應用程序（也可能是如Tomcat應用服務器運行）
2）model.reveng.xml：

<?xml version="1.0" encoding="UTF-8"?> 
<!DOCTYPE hibernate-reverse-engineering SYSTEM "http://www.hibernate.org/dtd/hibernate-reverse-engineering-3.0.dtd"> 
<hibernate-reverse-engineering> 
    <table-filter match-name=".*" package="ru.tomtrix.first.db"/> 
</hibernate-reverse-engineering> 

3）persistence.xml：

<?xml version="1.0" encoding="UTF-8"?> 
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" 
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
      xsi:schemaLocation="http://java.sun.com/xml/ns/persistence 
      http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> 

    <persistence-unit name="gomer" transaction-type="RESOURCE_LOCAL"> 
     <provider>org.hibernate.jpa.HibernatePersistenceProvider</provider> 
     <class>User</class> 
     <properties> 
      <property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/> 
      <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/> 
      <property name="hibernate.show_sql" value="true"/> 
      <property name="hibernate.connection.username" value="root"/> 
      <property name="hibernate.connection.password" value="1234"/> 
      <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/users"/> 
     </properties> 
    </persistence-unit> 
</persistence> 

Answer 1

問題是您缺少一部分配置。你需要告訴Spring你想（也）使用註解來進行配置。爲此，將<context:annotation-config />添加到您的配置中，並刪除entityManager

的設置旁邊的那個刪除工廠方法的調用spring將處理所有爲你。

添加提示使用的

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:context="http://www.springframework.org/schema/context" 
     xsi:schemaLocation=" 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 
     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd"> 

    <context:annotation-config /> 

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean"> 
     <property name="persistenceUnitName" value="gomer" /> 
    </bean> 

    <bean id="user" class="ru.tomtrix.first.db.UserHome" /> 

</beans> 

你的代碼的版本少架構INSEAD可能是有問題的，當你把它部署到茂盛的應用服務器，你可能會遇到的問題與Spring和EJB容器在控制競爭的豆子。休眠插件生成@Stateless會話bean，通常會被應用程序拾取。服務器（取決於你使用哪一個）。