查找按月分組的用戶帖子，unixtime

我想查找按月份分組的每個用戶的帖子數。我目前使用INT（10）unsigned來存儲帖子的日期。查找按月分組的用戶帖子，unixtime

什麼是一個超快速的方式來做到這一點？

CREATE TABLE IF NOT EXISTS `media` (
    `pid` int(10) unsigned NOT NULL AUTO_INCREMENT, 
    `class` tinyint(1) NOT NULL DEFAULT '1', 
    `date_class_changed` int(10) unsigned NOT NULL, 
    `title` char(5) CHARACTER SET latin1 COLLATE latin1_general_cs NOT NULL, 
    `url` varchar(1024) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `media` enum('image','video') CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `thumb` varchar(255) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `description` varchar(140) COLLATE utf8_unicode_ci NOT NULL, 
    `username` varchar(16) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `date` int(10) unsigned NOT NULL, 
    `file` varchar(1024) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `hash` char(32) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `hashtag` text CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `meta` varchar(255) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL, 
    `ip` int(10) unsigned NOT NULL, 
    `kind` tinyint(1) unsigned NOT NULL DEFAULT '0', 
    PRIMARY KEY (`pid`), 
    UNIQUE KEY `title` (`title`), 
    KEY `hash` (`hash`), 
    KEY `class_date` (`class`,`date_class_changed`), 
    KEY `username` (`username`) 
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1022724 ;

這是表，我說的是，我想顯示的帖子針對每個用戶對每個蒙，如數量：2012年9月，用戶X，N帖等。

從@fthiella的幫助後，我使用的查詢是：

SELECT 
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth, username, COUNT(*) as Posts 
FROM 
    media 
WHERE username = 'foobar' 
GROUP BY 1 
ORDER BY 1 DESC

感謝上帝它的速度不夠快，現在我會盡力的情況下，優化它不使用索引，但現在幾乎1M紀錄表現不俗。乾杯。

來源

2013-02-05 sathia

能否請您給您的數據的一個例子，你如何需要分組 – ManseUK

請添加表結構，例如數據和expeted結果 –

SELECT 
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth, 
    username, 
    COUNT(*) as Posts 
FROM 
    media 
GROUP BY 
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth, 
    username

來源

2013-02-05 12:23:16 fthiella

它拋出一個錯誤：＃1582 - 在調用不正確的參數個數DATE_FORMAT – sathia

SELECT DATE_FORMAT（FROM_UNIXTIME（'date'），'％Y-％m'）AS YearMonth，現在我會做一些測試，看看它是否足夠快。謝謝！ – sathia

查找按月分組的用戶帖子，unixtime

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