我想實現你在那裏輸入文本的彈出窗口,並把它添加到ListView但是我收到以下錯誤:該方法的getText()是未定義的類型的ListView
The method getText() is undefined for the type ListView
我的MainActivity .java代碼如下:
package com.mkyong.android;
import android.app.Activity;
import android.app.AlertDialog;
import android.content.Context;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.ListView;
public class MainActivity extends Activity {
final Context context = this;
private Button button;
private ListView result;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// components from main.xml
button = (Button) findViewById(R.id.buttonPrompt);
result = (ListView) findViewById(R.id.listView1);
// add button listener
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
// get prompts.xml view
LayoutInflater li = LayoutInflater.from(context);
View promptsView = li.inflate(R.layout.prompts, null);
AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(
context);
// set prompts.xml to alertdialog builder
alertDialogBuilder.setView(promptsView);
final ListView userInput = (ListView) promptsView
.findViewById(R.id.ListTitleDialogUserInput);
// set dialog message
alertDialogBuilder
.setCancelable(false)
.setPositiveButton("Create",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog,
int id) {
// get user input and set it to result
// edit text
result.setText(userInput.getText());
}
})
.setNegativeButton("Cancel",
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog,
int id) {
dialog.cancel();
}
});
// create alert dialog
AlertDialog alertDialog = alertDialogBuilder.create();
// show it
alertDialog.show();
}
});
}
}
感謝您的協助。
編輯:對於其中ListTitleDialogUserInput定義是如下用於prompts.xml的代碼;
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/layout_root"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="List Title: "
android:textAppearance="?android:attr/textAppearanceLarge" />
<EditText
android:id="@+id/ListTitleDialogUserInput"
android:layout_width="match_parent"
android:layout_height="wrap_content" >
<requestFocus />
</EditText>
</LinearLayout>
你究竟在做什麼'result.setText(userInput.getText());'這裏的結果和userInput都是Listview,所以getText或setText不適用.. – CRUSADER
我從http:// www複製了一個教程.mkyong.com/android/android-prompt-user-input-dialog-example /和他使用EditText,但我想在一個ListView中顯示結果。你能幫我嗎?謝謝。 – user2511675
爲什麼你的'userInput'是一個'ListView'?它不應該是一個'EditText'嗎?我們能否看到ID爲ListTitleDialogUserInput的視圖被定義的文件? –