2014-12-21 23 views
-1

我剛拿到這個Froala Editpr手,可悲的是,服務器集成腳本是用PHP編寫的,並用它在Asp.net網頁剃刀語法我..轉換這些PHP腳本到網頁剃刀語法

// Allowed extentions. 
$allowedExts = array("gif", "jpeg", "jpg", "png"); 

// Get filename. 
$temp = explode(".", $_FILES["file"]["name"]); 

// Get extension. 
$extension = end($temp); 

// An image check is being done in the editor but it is best to 
// check that again on the server side. 
// Do not use $_FILES["file"]["type"] as it can be easily forged. 
$finfo = finfo_open(FILEINFO_MIME_TYPE); 
$mime = finfo_file($finfo, $_FILES["file"]["tmp_name"]); 

if ((($mime == "image/gif") 
|| ($mime == "image/jpeg") 
|| ($mime == "image/pjpeg") 
|| ($mime == "image/x-png") 
|| ($mime == "image/png")) 
&& in_array($extension, $allowedExts)) { 
    // Generate new random name. 
    $name = sha1(microtime()) . "." . $extension; 

    // Save file in the uploads folder. 
    move_uploaded_file($_FILES["file"]["tmp_name"], getcwd() . "/uploads/" . $name); 

    // Generate response. 
    $response = new StdClass; 
    $response->link = "/uploads/" . $name; 
    echo stripslashes(json_encode($response)); 
} 
+0

如果(IsPost){ var文件= Request.Files [0]; var fileName = Path.GetFileName(file.FileName); var rootPath = Server.MapPath(「/ img/uploads /」); file.SaveAs(Path.Combine(rootPath,fileName)); var json = Html.Raw(Json.Encode(new {link = @「/ img/uploads /」+ fileName})); Response.ContentType =「text/plain」; Response.Write(json); Response.End(); } – user2095121

回答

1

嘗試這些碼塊

if(IsPost) { 
       var file = Request.Files[0]; 

     var fileName = Path.GetFileName(file.FileName); 
        var rootPath = Server.MapPath("/img/uploads/"); 
        file.SaveAs(Path.Combine(rootPath, fileName)); 

    //  Json.Write(fileSavePath, Response.Output); 
     var json = Html.Raw(Json.Encode(new { link = @"/img/uploads/" + fileName})); 
             Response.ContentType = "text/plain"; 
        Response.Write(json); 
        Response.End(); 
    }