的Android上傳響應消息預計不會

Question

這裏是我的Android代碼：

try 
     { 
     FileInputStream fileInputStream = new FileInputStream(new File(pathToOurFile3)); 

    URL url = new URL(urlServer); 
    connection = (HttpURLConnection) url.openConnection(); 

    // Allow Inputs & Outputs 
    connection.setDoInput(true); 
    connection.setDoOutput(true); 
    connection.setUseCaches(false); 

    // Enable POST method 
    connection.setRequestMethod("POST"); 

    connection.setRequestProperty("Connection", "Keep-Alive"); 
    connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); 

    outputStream = new DataOutputStream(connection.getOutputStream()); 
    outputStream.writeBytes(twoHyphens + boundary + lineEnd); 
    outputStream.writeBytes("Content-Disposition: form-data; name=\"profile\";filename=\"" + pathToOurFile3 +"\"" + lineEnd); 
    outputStream.writeBytes(lineEnd); 

    bytesAvailable = fileInputStream.available(); 
    bufferSize = Math.min(bytesAvailable, maxBufferSize); 
    buffer = new byte[bufferSize]; 

    // Read file 
    bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

    while (bytesRead > 0) 
    { 
    outputStream.write(buffer, 0, bufferSize); 
    bytesAvailable = fileInputStream.available(); 
    bufferSize = Math.min(bytesAvailable, maxBufferSize); 
    bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
    } 

    outputStream.writeBytes(lineEnd); 
    outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 

    // Responses from the server (code and message) 
    int serverResponseCode = connection.getResponseCode(); 
    String serverResponseMessage = connection.getResponseMessage(); 
    Log.d("serverResponseCode"+"", serverResponseCode +""); 
    Log.d("serverResponseMessage", serverResponseMessage); 

    fileInputStream.close(); 
    outputStream.flush(); 
    outputStream.close(); 
    } 
    catch (Exception ex) 
    { 
    Log.d("upload", ex.toString());//Exception handling 
    } 

這裏是PHP代碼：

<?php 
$target_path = "./"; 
$target_path = $target_path . basename($_FILES['profile']['name']); 
if(move_uploaded_file($_FILES['profile']['tmp_name'], $target_path)) { 
echo "The file ". basename($_FILES['profile']['name']). 
" has been uploaded"; 
} else{ 
echo "There was an error uploading the file, please try again!"; 
} 
?> 

該文件可以上傳到服務器。但是，響應消息與我預期的不同。
從Logcat，serverResponseCode is 200和serverResponseMessage is OK
但是從PHP，我想得到的消息，如" XXX has been upload"。
有誰知道如何得到消息？

Answer 1

我終於得到了答案：

InputStream is = connection.getInputStream(); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(
       is, "iso-8859-1"), 8); 
     StringBuilder sb = new StringBuilder(); 
     String line = null; 
     while ((line = reader.readLine()) != null) { 
      sb.append(line + "\n"); 
     } 
     is.close(); 
     String stringResponse = sb.toString(); 
     Log.d("response string:", stringResponse);