我必須顯示谷歌圖表根據下拉值,其中包含店鋪ID 我從MySQL檢索數據,沒有問題的價值觀,我檢索數據根據商店ID從ajax,並在輸入框中確認它也很好。更新谷歌圖表動態下拉使用AJAX和PHP
但我不知道如何用這些值更新該圖表,無需重新加載頁面。 這裏是我的谷歌圖表代碼與硬編碼值。
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>newChart</title>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawChart);
function drawChart()
{var data = google.visualization.arrayToDataTable([['Company & Model', 'Views'],['Samsung Hero Music E1232B',5],['Samsung Galaxy Y S5360',7],['Samsung Galaxy Ace S5830',7],['Karbonn K 1212',2],]);
var options = {
title: 'Most Popular Item ',
hAxis: {title: 'Brand', titleTextStyle: {color: 'red'}}};
var chart = new google.visualization.ColumnChart(document.getElementById('MPI_chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<h3>COLUMN CHART FOR MOST POPULAR ITEM </h3>
Select Shop <select id="MPI_selected_shop" onchange="MPI_set_shop(this.value);">
<option value="all_Shops">All Shops</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
</select>
<input type="text" id="sd" />
<div id="MPI_chart_div" style="width: 800px; height: 400px;"></div>
</body>
</html>
這裏是腳本標籤內的同一頁我的Ajax代碼
var xmlHttp
function MPI_set_shop(str)
{
alert(str);
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null)
{
alert ("Your browser does not support AJAX!");
return;
}
var url="chart.php";
url=url+"?q="+str;
alert(url);
xmlHttp.onreadystatechange=stateChanged;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
function stateChanged()
{
if (xmlHttp.readyState==4)
{
document.getElementById("sd").value=xmlHttp.responseText;
$st=xmlHttp.responseText;
alert($st);
}
}
這裏是我在哪裏從MySQL使用AJAX
<?php
$testid=0;
$testid=$_REQUEST["q"];
//echo $testid;
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
// Select Database
mysql_select_db("mysql", $con) or die('Could not connect: ' . mysql_error());;
$qMostPopularItem = "SELECT t.pr_id,p.pdt_company_name,p.pdt_model_name,SUM(t.count) AS count FROM tmp AS t INNER JOIN product_mapping AS p ON t.pr_id = p.pr_id AND t.shop_id =$testid GROUP BY pr_id ORDER BY t.count DESC;";
$mpi = mysql_query($qMostPopularItem,$con) or die('Could not fetch MPI: ' . mysql_error());
while($infoMPISW = mysql_fetch_assoc($mpi))
{
echo "['".$infoMPISW['pdt_company_name']." ";
echo $infoMPISW['pdt_model_name'] ."',";
echo $infoMPISW['count'],"],";
}
?>
謝謝你回覆卡邁勒。它爲我工作。 – Pramod
上述代碼中的數據是硬編碼的,它工作正常,但我從數據庫中獲取數據並將其存儲在變量中,並且該變量本身的格式(如我所願)意味着添加方括號和所有這些。但不是「顯示變量的值,而是顯示變量名稱,我應該如何解決它。 – Pramod
首先,我的anwser幫助過你,但到目前爲止,你正在傳遞一個字符串給ajax響應。數組本身,您可以使用json來獲取數據並作爲數組傳遞。 – Kamal