按字母順序排列分數和名稱，平均值，從最高到最低

Question

回到關於我的項目的另一個問題。所以我試圖在我的文本文件中按降序排列我的分數。但是，它會輸出語法錯誤。 當用戶輸入class_name時，上面創建的文件名是這樣，那麼什麼等於文件名。但是，它輸出一個錯誤。

這是我的一些代碼：

filename = class_name + ".txt"      
with open(filename, 'a+') as w:      
    w.write(str(name) + " : " + str(score) + '\n') 
    print("Your results are being updated ...") 
    time.sleep(2) 
    print("Your score has been updated") 
    print("") 
    w.close() 
if get_bool_input("Do you wish to view the previous results from your class: "): #The 'get_bool_input' will determine if they input yes or no and will either open the file or not. 
    selection= input("Do you wish to view the results in Alphabetical order(A), scores highest to lowest(B) or average score highest to lowest?(C)") 
    if selection == 'A': 
     with open(filename, 'r') as r: 
      for name in sorted(r): 
       print(name, end='') 
    if selection == 'B': 
     with open(filename, 'r') as r: 
      file_sorted = sorted((ast.literal_eval(x) for x in r),key=lambda z:(int(z[1]),z[0]),reverse=True)   
      r.close() 
    if selection not in ['A','B','C']: 
     print ("Error, type in A, B or C.") 

如何使它循環回「選擇=」的問題嗎？如果A，B或C未被選中。

if get_bool_input("Do you wish to view the previous results from your class: "): #The 'get_bool_input' will determine if they input yes or no and will either open the file or not. 
    selection= input("Do you wish to view the results in Alphabetical order(A), scores highest to lowest(B) or average score highest to lowest?(C)") 
    if selection == 'A': 
     print (alphabetically(data)) 
    if selection == 'B': 
     print (by_score(data)) 
    if selection == 'C': 
     print (by_average(data)) 

    if selection not in ['A','B','C']: 
     print ("Error, type in A, B or C.") 

else: 
    input ("Press any key to exit") 

編輯

像這樣的事情？

while True: 
    if selection == 'A': 
     print (alphabetically(data)) 
    elif selection == 'B': 
     print (by_score(data)) 
    elif selection == 'C': 
     print (by_average(data)) 
    return True 
    else: selection not in ['A','B','C']: 
     print ("Error, type in A, B or C.") 

Answer 1

第一個開放的，嘗試：

with open(filename, 'a+') as write_file: 
.... 

那麼第二個開做：

with open(filename, 'r+') as read_file: 
... 

也許它會工作

編輯

現在首先對您的文件的解析和分類方法，我想出了這個：

from collections import defaultdict 
from collections import OrderedDict 

filename = 'file.txt' 


def alphabetically(some_data): 
    return OrderedDict(
     (k, some_data[k]['scores']) 
     for k in sorted(some_data) 
    ) 


def by_score(some_data, descending=True): 
    return OrderedDict(
     (k, sum(some_data[k]['scores'])) 
     for k in sorted(some_data, 
         key=lambda k: sum(some_data[k]['scores']), 
         reverse=descending) 
    ) 


def by_average(some_data, descending=True): 
    def average(scores): 
     return float(sum(scores))/len(scores) 
    return OrderedDict(
     (k, average(some_data[k]['scores'])) 
     for k in sorted(some_data, 
         key=lambda k: average(some_data[k]['scores']), 
         reverse=descending) 
    ) 


data = defaultdict(dict) 
with open(filename, 'r+') as f: 
    for line in f.read().splitlines(): 
     name, score = line.split(' : ') 
     scores = data[name].get('scores', []) 
     scores.append(int(score)) 
     data[name]['scores'] = scores 

print alphabetically(data) 
print by_score(data) 
print by_average(data) 

輸出：

OrderedDict([('ADAM', [2]), ('Da', [3, 0, 1]), ('Dadsid', [4]), ('Davd', [3, 4]), ('Dliid', [9]), ('Dloed', [1]), ('Dsid', [3]), ('lukedd', [8]), ('mathe', [4, 12])]) 
OrderedDict([('mathe', 16), ('Dliid', 9), ('lukedd', 8), ('Davd', 7), ('Da', 4), ('Dadsid', 4), ('Dsid', 3), ('ADAM', 2), ('Dloed', 1)]) 
OrderedDict([('Dliid', 9.0), ('lukedd', 8.0), ('mathe', 8.0), ('Dadsid', 4.0), ('Davd', 3.5), ('Dsid', 3.0), ('ADAM', 2.0), ('Da', 1.3333333333333333), ('Dloed', 1.0)])