如何使用石英調度程序使用多個cron-triggers啓動作業？

我正在使用Quartz Scheduler在我的Java-App中啓動作業。我現在的工作HelloJob.java如何使用石英調度程序使用多個cron-triggers啓動作業？

package com.stackoverflow.test.java; 

import java.util.Date; 

import org.quartz.Job; 
import org.quartz.JobExecutionContext; 
import org.quartz.JobExecutionException; 

public class HelloJob implements Job { 

    private String message; 

    public HelloJob() { 
    Date akt = new Date(); 
    this.message = "Quartz is running (" + akt + ")."; 
    } 

    @Override 
    public void execute(JobExecutionContext context) throws JobExecutionException { 
    System.out.println(this.message); 
    } 

}

我想開始使用兩種不同的cron表達式（這裏：*/5 */3 * * * ?和*/9 */2 * * * ?）這份工作。我試過如下：

package com.stackoverflow.test.java; 

import org.quartz.JobDetail; 
import org.quartz.Scheduler; 
import org.quartz.SchedulerException; 
import org.quartz.Trigger; 
import org.quartz.impl.StdSchedulerFactory; 
import org.quartz.TriggerBuilder; 
import org.quartz.JobBuilder; 
import org.quartz.CronScheduleBuilder; 


public class TestQuartz { 

    public static void main(String[] args) { 

    try { 
     Scheduler scheduler = StdSchedulerFactory.getDefaultScheduler(); 
     scheduler.start(); 

     /* ################################################################### */ 

     JobDetail job = JobBuilder 
         .newJob(HelloJob.class) 
         .withIdentity("job1", "group1") 
         .build(); 

     CronScheduleBuilder sb1 = CronScheduleBuilder 
      .cronSchedule("*/5 */3 * * * ?"); 
     CronScheduleBuilder sb2 = CronScheduleBuilder 
      .cronSchedule("*/9 */2 * * * ?"); 

     Trigger trigger = TriggerBuilder 
      .newTrigger() 
      .withIdentity("trigger1", "group1") 
      .startNow() 
      .withSchedule(sb1) 
      .build(); 
     Trigger trigger2 = TriggerBuilder 
      .newTrigger() 
      .withIdentity("trigger2", "group1") 
      .startNow() 
      .withSchedule(sb2) 
      .build(); 

     scheduler.scheduleJob(job, trigger); 
     scheduler.scheduleJob(job, trigger2); 

     /* ################################################################### */ 

     Thread.sleep(10 * 60 * 1000); 
     System.out.println("FIN"); 

     /* ################################################################### */ 

     scheduler.shutdown(); 

    } catch (SchedulerException se) { 
     se.printStackTrace(); 
    } catch (InterruptedException e) { 
     e.printStackTrace(); 
    } 

    } 
}

我收到以下異常：

org.quartz.ObjectAlreadyExistsException: Unable to store Job : 'group1.job1', because one already exists with this identification. 
    at org.quartz.simpl.RAMJobStore.storeJob(RAMJobStore.java:279) 
    at org.quartz.simpl.RAMJobStore.storeJobAndTrigger(RAMJobStore.java:251) 
    at org.quartz.core.QuartzScheduler.scheduleJob(QuartzScheduler.java:886) 
    at org.quartz.impl.StdScheduler.scheduleJob(StdScheduler.java:249) 
    at com.stackoverflow.test.java.TestQuartz.main(TestQuartz.java:47)

是無法啓動一個工作與幾個觸發器？我可以以某種方式生成考慮多個cron表達式的計劃嗎？

來源

2015-04-02 Edward

您必須使用TriggerBuilder的forJob(JobKey jobKey)方法爲作業分配更多觸發器。

Trigger trigger = TriggerBuilder.newTrigger().forJob(job.getKey()). ... 
scheduler.scheduleJob(trigger)

在你的情況，應用了以下修改：

/* ... */ 
Trigger trigger2 = TriggerBuilder 
    .newTrigger() 
    .forJob(job.getKey()) 
    .withIdentity("trigger2", "group1") 
    .startNow() 
    .withSchedule(sb2) 
    .build(); 
/* ... */ 
scheduler.scheduleJob(trigger2); 
/* ... */

來源

2015-04-02 12:06:10 flo

如何使用石英調度程序使用多個cron-triggers啓動作業？

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