帶計數的唯一關聯數組

無法通過數組獲得以下方法。我打算將數組減少爲唯一值，但是，獲得每個獨特元素的總數。例如，獲得了最終的陣列，如：帶計數的唯一關聯數組

var data = [14:"A",5:"IMG",2:"SPAN"]

這對應於每一個獨特的標籤總的項目，與標籤本身相關聯。我原來的樣品陣列如下：

var data = ["A", "A","A","IMG","IMG","A","A","IMG","A","A","IMG","A","A","IMG","IMG","A","A","A","A","A","SPAN","SPAN"]

來源

2013-08-29 McRui

您可以對原始數組（或其深層副本）進行排序，然後對雙打進行計數。順便說一句。在你的例子中有14個「A」和6個「IMG」... – Teemu

http://mattgemmell.com/2008/12/08/what-have-you-tried/ – pckill

謝謝。但問題的確在於，使用與標籤相關的計數來構建新的關聯數組。 – McRui

你不能得到

var data = [14:"A",5:"IMG",2:"SPAN"]

因爲這不是有效的JavaScript。另外，如果計數最終會因爲不同的標籤而相似，您將得到重複的密鑰。開啓鍵/值左右，而使用JavaScript對象：

var reduced = {A: 14, IMG: 6, SPAN: 2};

在ECMAScript中5：

var data = ["A","A","A","IMG","IMG","A","A","IMG","A","A","IMG","A","A","IMG","IMG","A","A","A","A","A","SPAN","SPAN"]; 

var reduced = data.reduce(function (result, item) { 
    result[item] = (result.hasOwnProperty(item) ? result[item] : 0) + 1; 
    return result; 
}, {}); 

console.log(reduced); // Object {A: 14, IMG: 6, SPAN: 2}

的jsfiddle here

如果您需要支持的瀏覽器沒有「降低」，你可以找到減少underscore.js

var reduced = _.reduce(data, function (result, item) { 
    result[item] = (result.hasOwnProperty(item) ? result[item] : 0) + 1; 
    return result; 
}, {});

jsFiddle with underscore here

來源

2013-08-29 10:05:44

非常感謝您的努力和幫助。我更喜歡Ecmascript 5選項，因爲它返回一個對象，這使得它的使用更靈活。對於不支持減少...的瀏覽器WC - 誰在乎;）:)再次感謝！ – McRui

var data = ["A", "A", "A", "IMG", "IMG", "A", "A", "IMG", "A", "A", "IMG", "A", "A", "IMG", "IMG", "A", "A", "A", "A", "A", "SPAN", "SPAN"]; 
var temp = []; 
$.each(data,function(i,v){ 
if ($.inArray(v, temp) == -1) temp.push(data[i]); 
}); 
var count = []; 
var c = 0; 
$.each(temp,function(i,v){ 
    $.each(data,function (index, val) { 
    if (v == val) c++; 
    }); 
    count.push(c); 
    c = 0; 
}); 
var obj = {}; 
for (var i = 0; i < count.length; i++) { 
    obj[temp[i]] = count[i] 
} 
console.log(obj); //Object { A=14, IMG=6, SPAN=2}

http://jsfiddle.net/aqPb2/2/

來源

2013-08-29 09:57:03 rps

感謝您的幫助。我更喜歡下面的方法，它似乎更輕量級。謝謝！ – McRui

:)歡迎您 – rps

帶計數的唯一關聯數組

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