MySQL：JOIN語法+選擇內選擇=操作數錯誤

Question

我一直在摔跤這個查詢一段時間。那就是：

select First10.mal, Last10.family_name, 
(select * from gender2 
JOIN 
(select * from status) as Mix1 
JOIN 
(select * from age as Mix2 order by rand() limit 10) as Mix3 
JOIN 
(select incidentid from incidentid2 as Mix4) 
as Mix5 where data='mal' and incidentid='6' and status IN ('inj','ali') and age IN ('NULL','0-17') 
order by rand() limit 100) 
from (select fn.mal, @fns := @fns + 1 as Sequence 
from (select mal from fnames where mal IS NOT NULL order by rand() limit 100) fn, 
(select @fns := 0) vars) First10 
JOIN 
(select ln.family_name, @lns := @lns + 1 as Sequence 
from (select family_name from lastnames order by rand() limit 100) ln, 
(select @lns := 0) vars) Last10 
ON First10.Sequence = Last10.Sequence; 

我在這裏的目標是要插入將提出一項隨機姓氏，姓名，性別，身份，年齡，和事件ID的表。我已經嘗試了許多方法來返工這個腳本，包括分離該選擇語句，但我似乎總是與這個錯誤落得：

ERROR 1241 (21000): Operand should contain 1 column(s)

請告知你們，這已經現在強調我出去一會兒..這可能是一個非常簡單的答案，但我只是更加困惑自己。如果您需要任何澄清，請詢問。

Answer 1

好吧，它看起來像一個良好的睡眠和朋友的幫助後，我得到了這個查詢工作。對於那些正在尋找類似問題的答案，這裏是我如何得到這個工作：

select mal,family_name,data,age,status,incidentid 
from (select fn.mal, @fns := @fns + 1 as Sequence 
from (select mal from fnames where mal IS NOT NULL order by rand() limit 100) fn, 
(select @fns := 0) vars) as FN 
INNER JOIN 
(select ln.family_name, @lns := @lns + 1 as Sequence 
from (select family_name from lastnames order by rand() limit 100) ln, 
(select @lns := 0) vars) as LN 
INNER JOIN 
(select * from gender2) as Mix0 
INNER JOIN 
(select * from status) as Mix1 
INNER JOIN 
(select * from age as Mix2 order by rand() limit 3) as Mix3 
INNER JOIN 
(select incidentid from incidentid2 as Mix4) 
as Mix5 where data='mal' and incidentid='6' and status IN ('inj','ali') and age IN ('NULL','0-17') 
order by rand() limit 100;