Question

對於一些奇怪的原因，這行代碼是不工作：

var ajax = ajaxObj("POST", "php_parsers/status_system.php"); 

什麼可能呢？ 我覺得它必須是使用window.alert之後的那一行，因爲那行window.alert沒有運行。

全碼：

的函數被調用：

$status_ui = '<textarea id="statustext" onkeyup="statusMax(this,250)" placeholder="What&#39;s new with you '.$u.'?"></textarea>'; 
$status_ui .= '<button id="statusBtn" onclick="postToStatus(\'status_post\',\'a\',\''.$u.'\',\'statustext\')">Post</button>'; 

功能：

function postToStatus(action,type,user,ta){ 
    window.alert("status passed 1"); 
    var data = _(ta).value; 
    if(data == ""){ 
     alert("Type something first weenis"); 
     return false; 
    } 
    window.alert("status passed 2"); 
    _("statusBtn").disabled = true; 
    var ajax = ajaxObj("POST", "php_parsers/newsfeed_system.php"); 
    window.alert("status passed 3"); 
    ajax.onreadystatechange = function() { 
     if(ajaxReturn(ajax) == true) { 
      var datArray = ajax.responseText.split("|"); 
      if(datArray[0] == "post_ok"){ 
       var sid = datArray[1]; 
       data = data.replace(/</g,"&lt;").replace(/>/g,"&gt;").replace(/\n/g,"<br />").replace(/\r/g,"<br />"); 
       var currentHTML = _("statusarea").innerHTML; 
       _("statusarea").innerHTML = '<div id="status_'+sid+'" class="status_boxes"><div><b>Posted by you just now:</b> <span id="sdb_'+sid+'"><a href="#" onclick="return false;" onmousedown="deleteStatus(\''+sid+'\',\'status_'+sid+'\');" title="DELETE THIS STATUS AND ITS REPLIES">delete status</a></span><br />'+data+'</div></div><textarea id="replytext_'+sid+'" class="replytext" onkeyup="statusMax(this,250)" placeholder="write a comment here"></textarea><button id="replyBtn_'+sid+'" onclick="replyToStatus('+sid+',\'<?php echo $u; ?>\',\'replytext_'+sid+'\',this)">Reply</button>'+currentHTML; 
       _("statusBtn").disabled = false; 
       _(ta).value = ""; 
      } else { 
       alert(ajax.responseText); 
      } 
     } 
    } 
    ajax.send("action="+action+"&type="+type+"&user="+user+"&data="+data); 
    window.alert("status passed 4"); 
} 

newsfeed_system.php

if (isset($_POST['action']) && $_POST['action'] == "status_post"){ 
    // Make sure post data is not empty 
    if(strlen($_POST['data']) < 1){ 
     mysqli_close($db_conx); 
     echo "data_empty"; 
     exit(); 
    } 
    // Make sure type is a 
    if($_POST['type'] != "a"){ 
     mysqli_close($db_conx); 
     echo "type_unknown"; 
     exit(); 
    } 
    // Clean all of the $_POST vars that will interact with the database 
    $type = preg_replace('#[^a-z]#', '', $_POST['type']); 
    $data = htmlentities($_POST['data']); 
    $data = mysqli_real_escape_string($db_conx, $data); 

    // Insert the status post into the database now 
    $sql = "INSERT INTO newsfeed(author, type, data, postdate) 
      VALUES('$log_username','$type','$data',now())"; 
    $query = mysqli_query($db_conx, $sql); 
    $id = mysqli_insert_id($db_conx); 
    mysqli_query($db_conx, "UPDATE newsfeed SET osid='$id' WHERE id='$id' LIMIT 1"); 

    mysqli_close($db_conx); 
    echo "post_ok|$id"; 
    exit(); 
} 

的Ajax方法：

function ajaxObj(meth, url) { 
    var x = new XMLHttpRequest(); 
    x.open(meth, url, true); 
    x.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); 
    return x; 
} 
function ajaxReturn(x){ 
    if(x.readyState == 4 && x.status == 200){ 
     return true;  
    } 
} 

請幫忙！

Answer 1

ajax沒有被引用！您需要包含庫或將代碼調用爲'ajaxObj'。