檢查mysql數據表插入到

Question

我需要知道，如果我可以查詢和檢查數據庫表數據之前，php scrip將INSERT INTO表中？

我已經做了一個2字段的HTML和提交按鈕（POST），我也沒有添加數據到數據庫表的問題，並得到它的結果，但我有重複，我不想擁有它。 ..我想腳本來檢查我的數據，輸入的數據，如果沒有重複，然後添加它。

請協助。

謝謝

你的代碼

<?php 


$con=mysqli_connect("localhost","root","Opera1","railway"); 


if(mysqli_connect_errno()) 
{ 
echo "Failed to connect to MySQL: ", mysqli_connect_error; 
} 

$data1 = $_POST['data1']; 
$data2 = $_POST['data2']; 



$sql="replace into pipe (data1, data2) 
values ('$data1','$data2')"; 



if(!mysqli_query($con,$sql)) 
{ 
die('Error : ' . mysqli_error($con)); 
} 


echo "Record to Registraton added"; 

$result = mysqli_query($con,"SELECT * FROM pipe"); 

echo "<table border='1'> 
<tr> 
<th>Data1</th> 
<th>Data2</th> 
</tr>"; 

while($row = mysqli_fetch_array($result)) 
    { 
echo "<tr>"; 
    echo "<td>" . $row['data1'] . "</td>"; 
    echo "<td>" . $row['data2'] . "</td>"; 
    echo "</tr>"; 
    } 
echo "</table><br><br>"; 


mysqli_close($con); 


?> 

Answer 1

 <?php 


    $con=mysqli_connect("localhost","root","Opera1","railway"); 


    if(mysqli_connect_errno()) 
    { 
    echo "Failed to connect to MySQL: ", mysqli_connect_error; 
    } 

    $data1 = $_POST['data1']; 
    $data2 = $_POST['data2']; 

    $sql1="select * from pipe"; 
    $q1=mysql_query($con, $sql1); 
    $t=0; 
    while($row1=mysql_fetch_array($q1)) 
    { 

    if($row1['data1']== '$data1' || $row1['data2']=='$data2') 
    { 
    $t=1; 
    break; 
    } 
    } 
    if($t==1) 
    { 
     echo "Duplicate Entry!"; 
    } 
    else 
    { 

    $sql="replace into pipe (data1, data2) 
    values ('$data1','$data2')"; 



    if(!mysqli_query($con,$sql)) 
    { 
    die('Error : ' . mysqli_error($con)); 
    } 


    echo "Record to Registraton added"; 

    $result = mysqli_query($con,"SELECT * FROM pipe"); 

    echo "<table border='1'> 
    <tr> 
    <th>Data1</th> 
    <th>Data2</th> 
    </tr>"; 

    while($row = mysqli_fetch_array($result)) 
     { 
    echo "<tr>"; 
     echo "<td>" . $row['data1'] . "</td>"; 
     echo "<td>" . $row['data2'] . "</td>"; 
     echo "</tr>"; 
     } 
    echo "</table><br><br>"; 

    } 

    mysqli_close($con); 


    ?> 

Answer 2

如果你不想處理格蘭情況時有重複的只使用INSERT INTO忽略，而不是INSERT INTO。它可以像INSERT一樣工作，但如果有重複則不會失敗。

Answer 3

如果你想消除在1個行程重複的記錄，你可以使用REPLACE可用的命令在MySQL（參考：http://dev.mysql.com/doc/refman/5.0/en/replace.html）。如果具有相同值的行已經存在，那麼它將刪除現有行並添加新的其他行，它將插入新記錄。

你甚至可以尋找其他選項Insert into a MySQL table or update if exists