PL/SQL命令保持運行

Question

我有以下的PL/SQL函數：

CREATE OR REPLACE FUNCTION GETOVERUREN(v_user_id IN NUMBER, v_jaar IN NUMBER) 
RETURN NUMBER 
AS 
    v_resultaat number := 0; 
    v_min_uren_id number := 0; 
    v_max_uren_id number := 0; 
BEGIN 
    SELECT MIN(UREN_ID) INTO v_min_uren_id FROM UREN WHERE JAAR_NR = v_jaar AND UREN_ID IN (SELECT UREN_ID FROM GEBRUIKER_UREN g WHERE g.USER_ID = v_user_id); 
    SELECT MAX(UREN_ID) INTO v_max_uren_id FROM UREN WHERE JAAR_NR = v_jaar AND UREN_ID IN (SELECT UREN_ID FROM GEBRUIKER_UREN g WHERE g.USER_ID = v_user_id); 

    DECLARE 
     v_subtotaal number := 0; 
    BEGIN 
    v_max_uren_id := v_max_uren_id +1; 
    WHILE v_min_uren_id < v_max_uren_id LOOP 
     SELECT SUM(OMAANDAG+ODINSDAG +OWOENSDAG +ODONDERDAG +OVRIJDAG +OZATERDAG +OZONDAG) INTO v_subtotaal FROM UREN WHERE UREN_ID = v_min_uren_id; 

        ---------------------------------------------- 
        FIXED: v_min_uren_id := v_min_uren_id +1;(FORGOT TO + THE LOOP ITSELF) 
        ---------------------------------------------- 

        v_resultaat := v_resultaat + v_subtotaal; 
    END LOOP; 
RETURN v_resultaat; 
END; 
END; 

The following sql command should give the following outcome: 
SELECT GETOVERUREN(1,2013) FROM UREN; WHERE 1 is the userid and 2013 is the year 

GETOVERUREN(1,2013) 
------------------- 
      10.25 

But instead it gives: 

GETOVERUREN(1,2013) 
------------------- 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
      10.25 
Up to 157 times (wich is the total of rows i have in my table.) 

/*當我使用功能的SQLDeveloper保持運行，並不會停止運行的功能。我已經等了半個小時，但沒有結果。我做錯了什麼？ */

運行的問題是固定的，現在我得到了很多結果。

我自己做了一個例子功能看起來像這樣：

create or replace FUNCTION TESTING(v_user_id IN NUMBER) 
RETURN NUMBER 
AS 
    v_resultaat number := 0; 
BEGIN 
    SELECT IS_ADMIN INTO v_resultaat FROM GEBRUIKER WHERE USER_ID = v_user_id; 
    return v_resultaat; 
END TESTING; 

這個函數返回一個值，但其返回值X是在GEBRUIKER如此反覆的行數，什麼是錯的但我似乎無法弄清楚它是什麼。

Answer 1

你必須移動v_min_uren_id變量的增量內循環（這從最大改變MIN） - 否則，你會得到一個inifite循環。試試這個：

CREATE OR REPLACE FUNCTION GETOVERUREN(v_user_id IN NUMBER, v_jaar IN NUMBER) 
RETURN NUMBER 
AS 
    v_resultaat number := 0; 
    v_min_uren_id number := 0; 
    v_max_uren_id number := 0; 
BEGIN 
    SELECT MIN(UREN_ID) INTO v_min_uren_id FROM UREN WHERE JAAR_NR = v_jaar AND UREN_ID IN (SELECT UREN_ID FROM GEBRUIKER_UREN g WHERE g.USER_ID = v_user_id); 
    SELECT MAX(UREN_ID) INTO v_max_uren_id FROM UREN WHERE JAAR_NR = v_jaar AND UREN_ID IN (SELECT UREN_ID FROM GEBRUIKER_UREN g WHERE g.USER_ID = v_user_id); 

    DECLARE 
     v_subtotaal number := 0; 
    BEGIN 
    WHILE v_min_uren_id < v_max_uren_id LOOP 
     v_min_uren_id := v_min_uren_id +1; 
     SELECT SUM(OMAANDAG+ODINSDAG +OWOENSDAG +ODONDERDAG +OVRIJDAG +OZATERDAG +OZONDAG) INTO v_subtotaal FROM UREN WHERE UREN_ID = v_min_uren_id; 

     v_resultaat := v_resultaat + v_subtotaal; 
    END LOOP; 
RETURN v_resultaat; 
END; 
END;