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我有一週的日數,以及今年的週數。如何我可以在SQL計算當日的日期。對於2月22日的Example.the天數-2014是第7和它是year.Now的第8周我怎麼能計算日期從這個information.Its urgent.Please help.I回來想查詢。日期從週數和日在SQL Server 2012中
我有一週的日數,以及今年的週數。如何我可以在SQL計算當日的日期。對於2月22日的Example.the天數-2014是第7和它是year.Now的第8周我怎麼能計算日期從這個information.Its urgent.Please help.I回來想查詢。日期從週數和日在SQL Server 2012中
這裏是我的verison
create FUNCTION date_from_week_number_day
(
@year int = 2014
,@weeknumber int = 8
,@day int = 7
)
RETURNS date
AS
BEGIN
declare
@date date
,@first_date_of_year date
set @first_date_of_year = CONVERT(date,cast(@year as varchar(4))+'.1.1') --First calculate first day of year
set @date = dateadd(dd,@day -- we add days acoring of day of week
,dateadd(dd,-1*DATEPART(WEEKDAY,@first_date_of_year) --first day of year is not first day of week so we go back days how day has pass
, DATEADD(WEEK,@weeknumber-1,@first_date_of_year) --1. we go to week before last
)
)
return @date
END
,你可以調用這個
SET DATEFIRST 7
select dbo.date_from_week_number_day(2014,8,7)
試試這個
CREATE FUNCTION dbo.Date_From_WN_DN (@YearNum int,@WeekNum int,@DayNum int)
RETURNS Date AS
BEGIN
DECLARE @FirstDayYear As Date;
SET @FirstDayYear='01/01/' + CAST(@YearNum As varchar)
RETURN dateadd(d,((@DayNum)-datepart(weekday,@FirstDayYear)),dateadd(week, @WeekNum-1,@FirstDayYear))
END
SET DATEFIRST 7
SELECT dbo.DEV_VW_WeekSerial (2014,8,7)
O/P:
我建議找出WEEK0 = 1/1/YYYY(不管你一年),並找到DAY0 = 1/1/YYYY。並計算Julian0 =(WEEK0 * 7)+ DAY0。然後計算所述DAYOFYEAR =(8 * 7)+ 7.最後YourDate =使用DateAdd(1/1/YYYY + DAYOFYEAR = Julian0)。 – donPablo
whic天是第一週,如果是satuday是7 – adopilot
adopilot試試這個功能。其讓你clear..select DATEPART(DW,GETDATE()) –