2016-10-08 52 views
-1
int[] a = { 1, 2, 5, 2, 4, 6, 8, 9, 1, 19 }; 
int[] largestValues = new int[5]; 

    for (int i=0; i < 5; i++) { 
System.out.println(largestValues[i]); 
}` 

回答

0

您可以使用下面的代碼

對於EG。

public static void main(String args[]) { 
    int i; 
    int large[] = new int[5]; 
    int array[] = { 33, 55, 13, 46, 87, 42, 10, 34, 43, 56 }; 
    int max = 0, index; 
    for (int j = 0; j < 5; j++) { 
     max = array[0]; 
     index = 0; 
     for (i = 1; i < array.length; i++) { 
      if (max < array[i]) { 
       max = array[i]; 
       index = i; 
      } 
     } 
     large[j] = max; 
     array[index] = Integer.MIN_VALUE; 

     System.out.println("Largest " + j + " : " + large[j]); 
    } 
} 
+0

「Integer.MIN-VALUE」是做什麼的? –

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