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我在我的網站上有一個flickr供稿,並且我想在每張圖片下添加一個Pinterest「Pin-it」按鈕。如何構建Flickr Feed的Pin-It按鈕?
這裏的飼料腳本:
<script>
$.getJSON('http://api.flickr.com/services/feeds/photoset.gne?set=72157647581330595&[email protected]&lang=en-us&format=json&jsoncallback=?', function(data) {
$.each(data.items, function(i,item) {
var large = (item.media.m).replace('_m.jpg', '_b.jpg');
if(i <= 20){
$('#list').append('<li class="picture"><a class="slide-img" data-lightbox="engagement" href="' + large + '"><img src="' + large + '"/></a></li>');
}
});
});
</script>
我想將
<a href="http://www.pinterest.com/pin/create/button/?url=http%3A%2F%2Fwww.pushpinevents.com&media=http%3A%2F%2Ffarm4.staticflickr.com%2F3838%2F15273469932_0c3ceaeb96_b.jpg&description=%40PushPin%20Events" data-pin-do="buttonPin" data-pin-config="beside"><img src="//assets.pinterest.com/images/pidgets/pinit_fg_en_rect_gray_20.png" /></a>
代碼添加到.append
方法並替換URL字符串與圖像鏈接。
我最好的猜測是我需要從flickr網址定義一個變量,並用%2F等替換%3F':'。
因此,像:
var link = (large).replace('/', '%3F');
問題1 - 我怎樣才能更換一個.replace
方法多個字符?
說的已定義後,我的代碼下揮杆看起來像:
<script>
$.getJSON('http://api.flickr.com/services/feeds/photoset.gne?set=72157647581330595&[email protected]&lang=en-us&format=json&jsoncallback=?', function(data) {
$.each(data.items, function(i,item) {
var large = (item.media.m).replace('_m.jpg', '_b.jpg');
if(i <= 20){
$('#list').append('<li class="picture"><a class="slide-img" data-lightbox="engagement" href="' + large + '"><img src="' + large + '"/></a></li><br><a href="http://www.pinterest.com/pin/create/button/?url=http%3A%2F%2Fwww.pushpinevents.com&media='+link+'" data-pin-do="buttonPin" data-pin-config="beside">Pin It!</a>');
}
});
});
</script>
問題2 - 這是做到這一點的最有效方法是什麼?