編輯:我刪除了通用實現,並清理了這個響應,以更好地適應最初陳述的問題。
注:Marc Gravell的答案可能是最簡潔的,如果你只是想要給定類型的解析值。下面的答案顯示瞭如何獲取方法(即MethodInfo對象以及如何調用它)。
以下應該工作,至少對於實現公共靜態布爾的TryParse(字符串,T值)類型:
public static class Parsing
{
static MethodInfo findTryParseMethod(Type type)
{
//find member of type with signature 'static public bool TryParse(string, out T)'
BindingFlags access = BindingFlags.Static | BindingFlags.Public;
MemberInfo[] candidates = type.FindMembers(
MemberTypes.Method,
access,
delegate(MemberInfo m, object o_ignored)
{
MethodInfo method = (MethodInfo)m;
if (method.Name != "TryParse") return false;
if (method.ReturnParameter.ParameterType != typeof(bool)) return false;
ParameterInfo[] parms = method.GetParameters();
if (parms.Length != 2) return false;
if (parms[0].ParameterType != typeof(string)) return false;
if (parms[1].ParameterType != type.MakeByRefType()) return false;
if (!parms[1].IsOut) return false;
return true;
}, null);
if (candidates.Length > 1)
{
//change this to your favorite exception or use an assertion
throw new System.Exception(String.Format(
"Found more than one method with signature 'public static bool TryParse(string, out {0})' in type {0}.",
type));
}
if (candidates.Length == 0)
{
//This type does not contain a TryParse method - replace this by your error handling of choice
throw new System.Exception(String.Format(
"Found no method with signature 'public static bool TryParse(string, out {0})' in type {0}.",
type));
}
return (MethodInfo)candidates[0];
}
public static bool TryParse(Type t, string s, out object val)
{
MethodInfo method = findTryParseMethod(t); //can also cache 'method' in a Dictionary<Type, MethodInfo> if desired
object[] oArgs = new object[] { s, null };
bool bRes = (bool)method.Invoke(null, oArgs);
val = oArgs[1];
return bRes;
}
//if you want to use TryParse in a generic syntax:
public static bool TryParseGeneric<T>(string s, out T val)
{
object oVal;
bool bRes = TryParse(typeof(T), s, out oVal);
val = (T)oVal;
return bRes;
}
}
使用下面的測試代碼:
public bool test()
{
try
{
object oVal;
bool b = Parsing.TryParse(typeof(int), "123", out oVal);
if (!b) return false;
int x = (int)oVal;
if (x!= 123) return false;
}
catch (System.Exception)
{
return false;
}
try
{
int x;
bool b = Parsing.TryParseGeneric<int>("123", out x);
if (!b) return false;
if (x != 123) return false;
}
catch (System.Exception)
{
return false;
}
try
{
object oVal;
bool b = Parsing.TryParse(typeof(string), "123", out oVal);
//should throw an exception (//no method String.TryParse(string s, out string val)
return false;
}
catch (System.Exception)
{
//should throw an exception
}
return true;
}
}
而且在使用你的情況:
//input: string s, Config
Type tNum = Type.GetType(Config.numberType);
object oVal;
bool ok = Parsing.TryParse(tNum, s, out oVal);
//oVal is now of type tNum and its value is properly defined if ok == true
關於使用var:你可能會誤解var的作用:它是不是「變體」類型(類型對象已被用於此類型),但將該類型的聲明語法移至作業的右側。下面的聲明是等價的:
var i = 1; //the compiler infers the type from the assignment, type of i is int.
int i = 1; //type of i is int via declaration
var的主要用途是允許創建匿名類型:
var anon = new { Name = "abc", X = 123 };
`var`當前只在方法的範圍內可用。有關詳細信息,請參閱http://stackoverflow.com/q/4461597/1086351 – fcrick 2012-04-19 18:32:45