分割字符串分隔符

Question

假設我有串狀

Harry potter was written by J. K. Rowling 

如何使用was和by作爲分隔符分割字符串，並獲得導致C++載體？

我知道分裂使用多個字符，但不使用多個字符串。

Answer 1

如果使用C++ 11和鏗鏘有使用正則表達式字符串標記的解決方案：

#include <fstream> 
#include <iostream> 
#include <algorithm> 
#include <iterator> 
#include <regex> 

int main() 
{ 
    std::string text = " Harry potter was written by J. K. Rowling."; 

    std::regex ws_re("(was)|(by)"); 
    std::copy(std::sregex_token_iterator(text.begin(), text.end(), ws_re, -1), 
       std::sregex_token_iterator(), 
       std::ostream_iterator<std::string>(std::cout, "\n")); 


} 

輸出是：

Harry potter 
written 
J. K. Rowling. 

可悲的是gcc4.8沒有正則表達式完全集成。但鏗鏘編譯並正確鏈接。

Answer 2

暴力方法，而不是推動，沒有C++ 11，優化多人歡迎：

/** Split the string s by the delimiters, place the result in the 
    outgoing vector result */ 
void split(const std::string& s, const std::vector<std::string>& delims, 
      std::vector<std::string>& result) 
{ 
    // split the string into words 
    std::stringstream ss(s); 
    std::istream_iterator<std::string> begin(ss); 
    std::istream_iterator<std::string> end; 
    std::vector<std::string> splits(begin, end); 

    // then append the words together, except if they are delimiter 
    std::string current; 
    for(int i=0; i<splits.size(); i++) 
    { 
     if(std::find(delims.begin(), delims.end(), splits[i]) != delims.end()) 
     { 
      result.push_back(current); 
      current = ""; 
     } 
     else 
     { 
      current += splits[i] + " " ; 
     } 
    } 

    result.push_back(current.substr(0, current.size() - 1)); 
}