分組隨機序列爲對象

Question

我有一個文本文件的陣列，含有2種不同類型的數據：「名稱」和「動作」，每一種類型的重複隨機序列在整個文本文件：

NAME: joe 
ACTION: running 
NAME: paul 
ACTION: walking 
ACTION: swimming 
NAME: mary 
NAME: joe 
ACTION: sleeping 
NAME: paul 
NAME: mary 
NAME: ken 
ACTION: jumping 
ACTION: running 
ACTION: eating 

我試圖創建對象的數組，通過拼接每個類型的數據，使每個對象只能容納一對名稱和操作的，就像這樣：

{ 
    「name」: joe, 
    「action」 : running 
} 

{ 
    「name: paul, 
    「action」 : walking swimming 
} 

{ 
    「name: mary joe, 
    「action」 : sleeping 
} 

{ 
    「name: paul mary ken, 
    「action」 : jumping running eating 
} 

到目前爲止，我已經使用嘗試簡單的循環來逐行遍歷文本文件，檢查一行是否包含NAME或AC TION，但我無法弄清楚連接並將值推入數組的邏輯，而不會陷入困境。我正在學習JavaScript，並且可以真正使用一點幫助來解決這個問題，在此先感謝。

Answer 1

這裏有一個類似的解決方案，即凱文的。最大的區別是它創建新對象並將它們添加到數組中，而不是將它添加到現有值。希望能幫助到你！

var lines = `NAME: joe 
ACTION: running 
NAME: paul 
ACTION: walking 
ACTION: swimming 
NAME: mary 
NAME: joe 
ACTION: sleeping 
NAME: paul 
NAME: mary 
NAME: ken 
ACTION: jumping 
ACTION: running 
ACTION: eating` 


var entries = []; 
var current = null; 
lines.split("\n").forEach(function(entry) { 

    if (entry.indexOf('NAME:') > -1) { 

     var name = entry.substring(6); 

     // if the current instance hasn't been set yet, 
     // or there is already a value present, start a new object. 
     if (!current || current.action) { 
     current = { name: name, action: null }; 
     entries.push(current); 
     return; 
     } 

     // append the new name the current name list 
     current.name = `${current.name} ${name}`; 
     return; 
    } 

    // append the new action to the current action list. 
    // if action is null, just set the action as its initial value. 
    var action = entry.substring(8); 
    current.action = !current.action ? action : `${current.action} ${action}`; 
}); 

console.log(entries); 

Answer 2

您需要先按行分割文本字符串，然後遍歷每行並解析鍵和值。這裏有一個工作示例

var text = `NAME: joe 
 
ACTION: running 
 
NAME: paul 
 
ACTION: walking 
 
ACTION: swimming 
 
NAME: mary 
 
NAME: joe 
 
ACTION: sleeping 
 
NAME: paul 
 
NAME: mary 
 
NAME: ken 
 
ACTION: jumping 
 
ACTION: running 
 
ACTION: eating` 
 

 
// split the text in to an array of lines 
 
var lines = text.split("\n") 
 

 
var data = [] // the final mapped data 
 
var person = null // the person object to add actions to 
 

 
// loop through each line 
 
lines.forEach(function(line){ 
 
    
 
    // split the line into a key (NAME or ACTION) and the value 
 
    var vals = line.split(': ') 
 
    var key = vals[0] 
 
    var val = vals[1] 
 

 
    // if this line is for a new name, make a new "person" 
 
    if(key == 'NAME'){ 
 
    
 
    // save the current person to the final data 
 
    if(person) data.push(person) 
 
    
 
    // then create a new one 
 
    person = {name: val, actions: ''} 
 
    
 
    // add the action to the current person (if there is one) 
 
    }else if(person){ 
 
    person.actions += val 
 
    } 
 

 
}) 
 

 
console.log(data)

Answer 3

您可以使用.match()RegExp/NAME.+(?=\s\n)/g和/ACTION.+(?=\s\n)/g，以配合"NAME"和"ACTION"，.map()和.replace()開始的行與RegExp/^[A-Z:\s]+/更換"NAME"，"ACTION"，":"，和空格字符。

獲取最大陣列.length使用Math.max()設置爲for循環的最大迭代次數。 .push()新陣列對象;如果元素不在.length的數組索引處，請將空字符串""設置爲屬性的值。

var text = `NAME: joe 
 
ACTION: running 
 
NAME: paul 
 
ACTION: walking 
 
ACTION: swimming 
 
NAME: mary 
 
NAME: joe 
 
ACTION: sleeping 
 
NAME: paul 
 
NAME: mary 
 
NAME: ken 
 
ACTION: jumping 
 
ACTION: running 
 
ACTION: eating`; 
 

 
var [res, ...[names, actions]] = [[] 
 
           , text.match(/NAME.+(?=\s\n)/g) 
 
           , text.match(/ACTION.+(?=\s\n)/g) 
 
           ].map(function(arr) { 
 
            return arr.map(function(value) { 
 
             return value.replace(/^[A-Z:\s]+/, "") 
 
            }) 
 
            }); 
 

 
for (var i = 0; i < Math.max(names.length, actions.length); i++) { 
 
    res.push({name:names[i] || "", action: actions[i] || ""}) 
 
}; 
 

 
console.log(res);