這絕對適用所有你需要做的是使用NSMutableURLRequest
如下所示:
NSString* sXMLToPost = @"<?xml version=\"1.0\"?><Name>user</Name>";
NSData* data = [sXMLToPost dataUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:@"http://myurl.com/RequestHandler.ashx"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:[sXMLToPost dataUsingEncoding:NSUTF8StringEncoding]];
NSURLResponse *response;
NSError *error;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
if (error) {
//handle the error
}
在ASHX文件
而且現在解析InputStream
讀取XML發佈:
System.IO.Stream str; String strmContents;
Int32 counter, strLen, strRead;
str = Request.InputStream;
strLen = Convert.ToInt32(str.Length);
byte[] strArr = new byte[strLen];
strRead = str.Read(strArr, 0, strLen);
// Convert byte array to a text string.
strmContents = "";
for (counter = 0; counter < strLen; counter++)
{
strmContents = strmContents + strArr[counter].ToString();
}
記住,你可以使用隨時查詢請求類型:
如果(context.Request.RequestType == 「POST」)
MSDN HttpRequest.InputStream
有關您的問題的任何更新? – 2011-05-04 12:28:22
謝謝AhmadTK。我還沒有嘗試過代碼示例,因爲我的iPhone團隊尚未開始使用它。看起來這正是我想要的,並且會工作。稍後會更新你..謝謝... – Anand 2011-05-05 07:27:08
我很高興聽到這個消息,只要你們準備好了,請告訴我你是否需要任何幫助。 – 2011-05-05 07:40:30