嘗試查找字符串的計數數字

Question

String at = "123123"; 
     for (int i = 0; i <at.length() ; i++) { 
      if (at.charAt(i)==1){ 
       int count=0; 
       count++; 
      } 
     } 

Want 1出現2次。我失敗的地方。謝謝。

Answer 1

String at = "123123"; 
int count = 0; // Move out 
for (int i = 0; i < at.length(); i++) { 
    if (at.charAt(i) == '1'){ // Compare with the char '1' 
    count++; 
    } 
} 
// count is 2 here. 

Answer 2

String at = "123123"; 
    int count = 0;//outside the loop 
    int oneDigitCount = 0; 
    for (int i = 0; i < at.length(); i++) { 
     if (Character.isDigit(at.charAt(i))) {//digit count 
      count++; 
     } 
     if(at.charAt(i)=='1'){//count ones in string 
      oneDigitCount++; 
     } 
    }