Javascript OOP初始化和方法調用問題

Question

我有一個javascript類person，我做了Obj它，工作正常。但我需要從person類訪問功能。

當我試圖訪問我得到..not a function error。

請幫忙！

重要......我需要初始化'person'類，並調用與我的代碼完全相同的方法。怎麼樣？？幫幫我！

這裏是我的代碼：

var person = { 
    setBasic: function(data) { 
    alert(data.name + ' ' + data.age); 
    }, 
    this:getPerson = function() { 
    alert('get me'); 
    }, 
    success: null 
}; 

//lets instantiate.enter code here 

var perObj = new person.setBasic({ 'name': 'ikair', 'age': 33, }); 

// works fine.. 

//now I need to call a function of person class: 

perObj.getPerson(); 

//not working :(... how to call function with prev code? 

Answer 1

function person() { 
    this.setBasic = function(data) { 
    alert(data.name + ' ' + data.age); 
    }; 
    this.getPerson = function() { 
    alert('get me'); 
    }; 
} 

var perObj = new person(); 
perObj.setBasic({ name: 'ikair', age: 33 }); 
perObj.getPerson(); 

更新：

var person = { 
    setBasic: function(data) { 
    alert(data.name + ' ' + data.age); 

    this.getPerson = function() { 
     alert('get me'); 
    }; 
    } 
}; 

var perObj = new person.setBasic({ name: 'ikair', age: 33 }); 
perObj.getPersion(); 

Answer 2

試試這個

var person = { 
    setBasic: function(data) { 
    alert(data.name + ' ' + data.age); 
    }, 
    getPerson: function() { 
    alert('get me'); 
    }, 
    success: null 
    }; 
    person.setBasic({ 'name': 'ikair', 'age': 33, }); 
    person.getPerson(); 

Answer 3

你需要一個類，並給它的原型功能：

/** 
* Person class 
* @param {String} name Name of person 
* @param {Number} age Age of person 
*/ 
function person(name, age) { 
    this.name = name || ""; 
    this.age = age || 0; 
    this.success = null; 
} 
person.prototype = { 
    /** 
    * Set the parameters of this object 
    * @param {type} data 
    * @returns {undefined} 
    */ 
    setBasic: function(data) { 
     this.name = data.name; 
     this.age = data.age; 

     alert(data.name + ' ' + data.age); 
     // Do you mean to use this? 
     alert(this.name + ' ' + this.age); 
    }, 
    /** 
    * Alert out fields 
    * @returns {undefined} 
    */ 
    getPerson: function() { 
     alert(this.name + ' ' + this.age); 
     alert('get me'); 
    } 
}; 

/** 
* Make a person and print him out 
* @returns {undefined} 
*/ 
function main() { 
    var perObj = new person("bob", 33); 
    perObj.setBasic({ 
     name: "akira", 
     age: 100 
    }); 
    perObj.getPerson(); 
} 

Answer 4

其他的答案都是有效的，但你也可以調整你的代碼是這樣簡單得多：

function Person(data){ 
    this.age = data.age; 
    this.name = data.name; 
}; 

Person.prototype.getData = function(){ 
    alert(this.name + " " + this.age); 
}; 

var john = new Person({name: "John", age: 43}); 
john.getData(); 

而一個的jsfiddle來證明它的作品here