從MYSQL查詢填充文本框

我需要查詢數據庫，然後用結果填充文本框輸入。從MYSQL查詢填充文本框

我想

調用日期：

<td> 
     <?php 
     $selectedSPK=$_POST['SPKSelect']; 
     $assigned = $_POST['Sales_Exec']; 
     $date = $_POST['DateSelect']; 

if ($selectedSPK) 

{ 
    $Call1query = "SELECT Call1 FROM Data WHERE SPKCustNo = '$selectedSPK' "; 

$Call1result = mysql_query($Call1query); 


while($row = mysql_fetch_array($Call1result)){ 
    $Call1 = $row["$Call1Result"]; 

    } 

} 
?> 
    <input type="text" name="Call1" id="Call1" value="<?php echo(htmlspecialchars($Call1)); ?>"/></td>

但是卻一無所獲了，我要去哪裏錯了，文本輸入看上去棘手的填充！

謝謝！

來源

2012-10-03 Chris Spalton

你不能做到這一點...'$ CALL1 = $行[ 「$ Call1Result」];'...給在'字段名$ row' –

更換

$Call1 = $row["$Call1"];

與

$Call1 = $row["Call1"];

來源

2012-10-03 10:47:08

Thankyou，工作完美！ –

改用

$Call1 = $row["Call1"];

來源

2012-10-03 10:47:32 triclosan

太棒了！ Thankyou，只要定時器讓我回答，就會標記爲答案。 –

的問題是在這裏改變

$Call1 = $row["$Call1Result"];

到

$Call1 = $row['Call1']; //here column name comes not variable name

來源

2012-10-03 10:48:46

嘗試這樣

<td> 
    <?php 
    $selectedSPK=$_POST['SPKSelect']; 
    $assigned = $_POST['Sales_Exec']; 
    $date = $_POST['DateSelect']; 

if ($selectedSPK) 

{ 
$Call1query = "SELECT Call1 FROM Data WHERE SPKCustNo = '$selectedSPK' "; 

$Call1result = mysql_query($Call1query); 


while($row = mysql_fetch_array($Call1result)){ 
$Call1 = $row["Call1"]; 

} 

}?> 

<input type="text" name="Call1" id="Call1" value="<?php echo(htmlspecialchars($Call1)); ?>"/></td>

來源

2012-10-03 11:00:00

從MYSQL查詢填充文本框

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