打印文本在一行

Question

下面的代碼打印這樣的文字：

John 
    Smith 
    02/07/1234 

首先，它縮進兩個行，我將如何改變代碼以打印爲： John Smith 02/07/1234上一個線？

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print (forename, surname, birthdate) 

Answer 1

嘗試：

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print("{} {} {}".format(forename.strip(' \t\n\r'), surname.strip(' \t\n\r'), birthdate.strip(' \t\n\r'))) 

的.strip（ '\ t \ n \ r'）除去開頭和結尾的標籤和空格，該.format（）格式，您的字符串以可控的方式進行打印。

Answer 2

使用.join並從每個名稱中去掉空格。

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print(' '.join([forename.strip(), surname.strip(), birthdate.strip()])) 

Answer 3

由於您的問題沒有明確指定的Python，你可能想知道，你不需要任何程序可言，如果你是一個unixoid系統（BSD，Linux和Mac OSX版）上：只使用paste shell命令：

paste -d ";" forename surname birthday 

將產生

John;Smith;02/07/1234 

如果不指定-d標誌，標籤將被用於條目分開。您可以瞭解更多關於paste這裏：https://en.wikipedia.org/wiki/Paste_(Unix)

Answer 4

with open("Forename") as f1, open("Surname") as f2, open("Date of birth") as f3: 
    for forename, surname, birthdate in zip(f1,f2,f3): 
     print (forename, surname, birthdate, end=' ')