Mysql準備語句 - 請選擇

Question

誰能給我一個建議？爲什麼查詢不能提供給我預期的價值？謝謝。

$mysqli = new mysqli($GLOBALS["mysql_host"], $GLOBALS["mysql_user"],   $GLOBALS["mysql_passwd"], $GLOBALS["mysql_database"]); 
$stmt = $mysqli->prepare("SELECT one FROM table ORDER BY date DESC LIMIT 1"); 
$last = $stmt->bind_result($one); 
$stmt->execute(); 
$stmt->close(); 
$mysqli->close(); 

Echo $last; //it should be "abc" 

Answer 1

我認爲你必須execute，然後調用fetch上mysql_stmt -objects。 因爲您可能會得到多個結果（行）。

隨着fetch你會提高你的結果 - 遊標。

文檔： mysqli mysqli-stmt

<?php 
$mysqli = new mysqli("localhost", "my_user", "my_password", "world"); 

if (mysqli_connect_errno()) { 
    printf("Connect failed: %s\n", mysqli_connect_error()); 
    exit(); 
} 

/* prepare statement */ 
if ($stmt = $mysqli->prepare("SELECT Code, Name FROM Country ORDER BY Name LIMIT 5")) { 
    $stmt->execute(); 

    /* bind variables to prepared statement */ 
    $stmt->bind_result($col1, $col2); 

    /* fetch values */ 
    while ($stmt->fetch()) { 
     printf("%s %s\n", $col1, $col2); 
    } 

    /* close statement */ 
    $stmt->close(); 
} 
/* close connection */ 
$mysqli->close(); 

?> 

Answer 2

我可以。
一個的建議是簡單明瞭的：不使用的mysqli

使用PDO代替

$stmt = $pdo->prepare("SELECT one FROM table ORDER BY date DESC LIMIT 1"); 
$stmt->execute(); 
$last = $stmt->fetchColumn(); 

echo $last; //it should be "abc" 

乾淨，簡單，工作