的Java如何跳回While循環

Question

所以，如果LARGE不等於Count，然後LARGE應該遞增，直到Count和LARGE具有相同的值。事情發生之後，我的教授想再次輸入一個新的整數，然後它會再次循環，但我不知道如何讓我的代碼回到while。

if (LARGE == Count) 
{ 
    System.out.println ("Large is Equal to Count"); 
} 

while (Count != LARGE) 
{ 
    LARGE++; 
    System.out.println ("Large is " +LARGE); 
} 

if (LARGE == Count) 
{ 
    System.out.println ("Input a new integer to compare") 
    LARGE = input.newInt(); 
} 

Answer 1

根據我的理解，這是你想要的。

public static void main(String[] args) { 

     int LARGE = 0; 
     int Count = 0; 
     String s = null; 
     Scanner sc = new Scanner(System.in); 
     do { 

      LARGE = sc.nextInt(); 
      Count = sc.nextInt(); 

      if (LARGE == Count) { 
       System.out.println("Large is Equal to Count"); 
      } else { 
       do { 
        LARGE++; 
        System.out.println("Large is " + LARGE); 
       } while (Count != LARGE); 

       if (LARGE == Count) { 
        System.out.println("Large is Equal to Count"); 
        System.out.println("Input a new integer to compare"); 
       } 

      } 

      System.out.println("Do you want to continue? If yes then Press Y"); 
      s = sc.next(); 
     } while (s.equalsIgnoreCase("Y")); 

    } 

Answer 2

教授多少次想輸入新的整數，永遠？ 我假設它1000次。 如果永遠代替「時間」爲true，而括號別的分配的東西有意義的「次」，而不是1000

System.out.println ("Input a new integer to compare") 
LARGE = input.newInt(); 
int times = 1000; // number of times prof want to enter new integer. 
int loop = 0; 
while(times > loop){ 
    while (Count != LARGE) 
    { 
     LARGE++; 
     System.out.println ("Large is " +LARGE); 
    } 
    System.out.println ("Input a new integer to compare") 
    LARGE = input.newInt(); 
    loop++; 
}