問題是與您查詢的是,你不能排除有suppliers
是該產品有一些其他屬性的產品,所以你可以使用NOT EXIST
或NOT IN
,我已經寫了使用NOT EXIST
查詢。
SELECT *
FROM wp_posts wp
INNER JOIN wp_postmeta wm ON wm.`post_id` = wp.`ID`
INNER JOIN wp_term_relationships wtr ON (wp.`ID` = wtr.`object_id`)
INNER JOIN wp_term_taxonomy wtt ON wtr.`term_taxonomy_id` = wtt.`term_taxonomy_id`
INNER JOIN wp_terms wt ON wt.`term_id` = wtt.`term_id`
WHERE post_type = 'product'
AND NOT EXISTS
(SELECT `object_id`
FROM `wp_term_relationships` AS wtr_inner
WHERE `term_taxonomy_id` IN
(SELECT term_taxonomy_id
FROM `wp_term_taxonomy`
WHERE `taxonomy` = 'suppliers')
AND wtr.object_id = wtr_inner.object_id)
GROUP BY wp.ID
另一個版本,這將是一個快一點,如果你知道所有的suppliers
term_taxonomy_id
所以,你可以修改上面的查詢作爲
SELECT *
FROM wp_posts wp
INNER JOIN wp_postmeta wm ON wm.`post_id` = wp.`ID`
INNER JOIN wp_term_relationships wtr ON (wp.`ID` = wtr.`object_id`)
INNER JOIN wp_term_taxonomy wtt ON wtr.`term_taxonomy_id` = wtt.`term_taxonomy_id`
INNER JOIN wp_terms wt ON wt.`term_id` = wtt.`term_id`
WHERE post_type = 'product'
AND NOT EXISTS
(SELECT `object_id`
FROM `wp_term_relationships` AS wtr_inner
WHERE `term_taxonomy_id` IN (27,28,29) -- replace it will all suppliers term_taxonomy_id
AND wtr.object_id = wtr_inner.object_id)
GROUP BY wp.ID
希望這有助於!