我有一個問題,節省JSON在示波器上,我已經一個功能節省了JSON成一個範圍和完美的作品,但第二個將不保存...JSON不會節省範圍AngularJS
servicoLeituraPosts.php返回JSON數據 servicoLeituraComments.php返回JSON與範圍數據
均通過URL發送JSON正確,和第一位顯示數據,但第二個不和這正是做這樣的第一個,所以我不明白是怎麼回事。
第一個將JSON保存到$ scope.posts,它有數據,我可以打印它 第二個將JSON保存到$ scope.comments中,如果我打印它,它是空白的?爲什麼?謝謝你的幫助,但我是AngularJS的初學者。
<script>
var app = angular.module('postsApp', []);
var interval;
app.controller('postsCtrl', function($scope) {
$scope.toggle = false;
$scope.texto = [];
$scope.comment = [];
$scope.comment = "";
$scope.comments = [];
$scope.posts = [];
$scope.texto = "";
$scope.idPost = 0;
$scope.showBox = function(p){
p.toggle = !p.toggle;
if(interval == 0){
interval = setInterval("angular.element($('#postsApp')).scope().servicoLeituraPosts()",1000);
}else{
clearInterval(interval);
interval = 0;
}
$scope.servicoLeituraComments(p);
console.log($scope.comments);
console.log($scope.posts);
};
$scope.iniciaTimer = function(){
interval = setInterval("angular.element($('#postsApp')).scope().servicoLeituraPosts()",1000);
};
$scope.servicoLeituraPosts = function(){
$.getJSON(
"servicoLeituraPosts.php",
{
},
function(jsonData)
{
$scope.posts = jsonData;
$scope.$apply();
});
};
$scope.servicoLeituraComments = function(p){
$.getJSON(
"servicoLeituraComments.php",
{
"idPost": p.idPost
},
function(jsonData)
{
$scope.comments = jsonData;
$scope.$apply();
});
console.log($scope.comments);
};
$scope.addPost = function(){
$.post(
"addPostRest.php",
{
"texto" : $scope.texto
},
function(dados)
{
$scope.texto = dados.indexOf("OK") >= 0 ? "" : "FALHOU";
$scope.$apply();
}
);
};
$scope.addLike = function(idPost){
$.post(
"addLike.php",
{
"idPost" : $scope.idPost = idPost
},
function(dados)
{
$scope.texto = dados.indexOf("OK") >= 0 ? "" : "FALHOU";
$scope.$apply();
}
);
};
$scope.addComment = function(p){
$.post(
"addComentarioRest.php",
{
"comment" : p.comment,
"idPost" : p.idPost
},
function(dados)
{
$scope.texto = dados.indexOf("OK") >= 0 ? "" : "FALHOU";
$scope.$apply();
}
);
};
});
</script>
部分信用? :) –