選擇器中的表達式Func

Question

我使用Exp-Func創建了兩個選擇器我想在單個查詢中執行這兩個選擇器。代碼如下：

Expression<Func<Scholar, ScholarCultureWatchListView>> selector = z => new ScholarCultureWatchListView 
{ 
    ScholarId = z.ID, 
    Name = z.FirstName + " " + z.LastName            
}; 

Expression<Func<Scholar, ScholarCultureWatchListView>> selector2 = z => new ScholarCultureWatchListView 
{ 
    Grade = z.CurrentGrade 
}; 
var result= from s in db.Scholars 
      select new ScholarCultureWatchListView 
       { 
      **?????What is write here (selector, selector2)** 
       } 



public class ScholarCultureWatchListView 
{ 
    public long ScholarId { get; set; } 
    public string Name { get; set; } 
    public Grade? Grade { get; set; } 
    public bool? HoldOverSkip { get; set; } 
    public Grade? GradeHoldOver { get; set; } 
    public bool? Iep { get; set; } 
    public int Tardies { get; set; } 
    public int Absences { get; set; } 
    public int YtdSuspensions { get; set; } 
    .... 
} 

請解決我的問題。 感謝

Answer 1

如果你想從一個單一的調用返回ScholarCultureWatchListView兩個單獨的實例，例如，你可以做這（和你不需要選擇全部）：

var result = from s in db.Scholars 
      select new[] 
      { 
       new ScholarCultureWatchListView 
       { 
        ScholarId = s.ID, 
        Name = s.FirstName + " " + z.LastName 
       }, 
       new ScholarCultureWatchListView 
       { 
        Grade = z.CurrentGrade 
       }, 
      };