1
:使用JsonPath當你不知道,如果你正在處理給出下面的JSON對象或數組
{
"store": {
"book": [
{
"category": "reference",
"author": "Nigel Rees",
"title": "Sayings of the Century",
"price": 8.95
},
{
"category": "fiction",
"author": "Evelyn Waugh",
"title": "Sword of Honour",
"price": 12.99
},
{
"category": "fiction",
"author": "Herman Melville",
"title": "Moby Dick",
"isbn": "0-553-21311-3",
"price": 8.99
},
{
"category": "fiction",
"author": "J. R. R. Tolkien",
"title": "The Lord of the Rings",
"isbn": "0-395-19395-8",
"price": 22.99
}
],
"bicycle": {
"color": "red",
"price": 19.95
}
},
"expensive": 10
}
我們可以像使用$.store.book[*].author
路徑表達式得到所有的作者。但是如果我們事先不知道book
是一個數組還是一個對象,例如如果我們能有什麼上述JSON而且這樣的事情:
{
"store": {
"book": {
"category": "reference",
"author": "Nigel Rees",
"title": "Sayings of the Century",
"price": 8.95
},
"bicycle": {
"color": "red",
"price": 19.95
}
},
"expensive": 10
}
是否有可能被用於獲取在任何情況下所有的作者是「通用路徑」?
有什麼辦法可以在路徑中包含'book'?如果有書 - >作者和期刊 - >作者,我會從這條道路上得到兩組作者,對吧?如果我只想取回書籍作者,該怎麼辦? – Adam
當然。然後你可以編寫:$ .store.book..author,它也可以用於兩種JSON形狀,僅當「書」(s)中的後代捕獲「作者」時, – YSharp