3DTouch UIPreviewAction：performseguewithidentifier not working

Question

我在我的iOS Swift應用程序中實現了一些窺視UIPreviewActions。但是，這些行爲會執行被忽略的延期交易。我怎麼能做到這一點？

有一個類似的問題，但在Objective-C：UIPreviewAction to Mail From Peek

override func previewActionItems() -> [UIPreviewActionItem] { 
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in 
    self.performSegueWithIdentifier("segueID", sender: self) 
    } 
    return [performSegueAction] 
} 

Answer 1

對不起已故的答覆，但最近張貼這樣的情況下，別人的答案就遇到了這個自己認爲有用...

當您調用UIPreviewAction中的處理程序時，視圖控制器已從層次結構中刪除，因此執行segse不起作用。相反，你應該這樣做：

class PreviewViewController: UIViewController { 

var performAction: (() -> Void)? 

override func previewActionItems() -> [UIPreviewActionItem] { 
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in 
     self.performAction?() 
    } 
    return [performSegueAction] 
} 

而且在父控制器（您將從這裏啓動預覽）：

class ParentViewController: UIViewController { 

override func prepare(for segue: UIStoryboardSegue, sender: Any?) { 
    if let vc = segue.destination as? PreviewViewController { 
     vc.handleAction = { 
      self.performSegueWithIdentifier("segueID", sender: self) 
     } 
    } 
    inject(toController: segue.destination) 
}