我想創建包含其他自定義控件的自定義控件,並使用ngModel連接所有這些自定義控件。 像:將ngModel中的對象傳遞給自定義控件Angular2
PersonSearchComponent:
- DeveloperSearchControl
- 名稱 - 一些字符串輸入
- 姓
- ProffesionSelect - 自定義控件期待ProffesionModel
- BuildingSearchControl
- 這裏有些自定義控件
- CountryCustomControl - 自定義控件期待CountryModel
- PersonListComponent: 有關的一些服務從PersonSearchComponent項目-imported數據
- SomeOtherSearchComponent
- DeveloperSearchControl - 可重複使用的
所以現在我已經工作版本,但我想我已經取得了壞事(也許我應該用FormBuilder):
PersonSearch模板:
種<div>
<developer-search-control [(ngModel)]="searchModel.developerSearchModel"></developer-search-control>
<building-search-control [(ngModel)]="searchModel.buildingSearchModel"></building-search-control>
<country-select [(ngModel)]="searchModel.countryModel"><country-select>
</div>
ParentSearch部件
...
export class PersonSearch {
@Output() searchDataEmitter= new EventEmitter();//Exports data to above component which contains this, and listComponent
searchModel : PersonSearchModel : new PersonSearchModel();
performSearch()
{
//gets data from service with searchModel and searchDataEmitter transpors it to above component
}
}
型號: PersonSearchModel:
developerSearchModel : DeveloperSearchModel = new DeveloperSearchModel();
buildingSearchModel: BuildingSearchModel = new BuildingSearchModel();
countryModel : CountryModel;
DeveloperSearchModel:
name : string
surname : string
proffesion : ProfessionModel
模板 developerSearchControl.component.html:
<div *ngIf="value">//This is the problem
<input [(ngModel)]="value.name"></input>
<input [(ngModel)]="value.surname"></input>
<profesion-select [(ngModel)]="value.ProffesionSelect">
</div>
developerSearchControl.component:
...
@Component({
selector: 'developer-search-control',
templateUrl: './developerSearchControl.component.html',
providers: [{
provide: NG_VALUE_ACCESSOR,
useExisting: forwardRef(() => DeveloperSearchControlComponent),
multi: true,
}],
})
export class DeveloperSearchControlComponent extends ElementBase<DeveloperSearchModel > {
protected model: NgModel;
constructor(
@Optional() @Inject(NG_VALIDATORS) validators: Array<any>,
@Optional() @Inject(NG_ASYNC_VALIDATORS) asyncValidators: Array<any>,
) {
super(validators, asyncValidators);
}
}
profesionSelect。組件
...
@Component({
selector: 'profesion-select',
template: `
<div>
<label *ngIf="label">{{label}}</label>
<dx-select-box
[dataSource]="data"
[(ngModel)]="value"
displayExpr="proffesionName"
[placeholder]="placeholder"
[searchEnabled]="true"
>
</dx-select-box>
</div>`,
providers: [{
provide: NG_VALUE_ACCESSOR,
useExisting: ProfessionComponent,
multi: true,
}],
})
export class ProfessionComponent extends ElementBase<string> implements OnInit {
private data: ProfessionModel[];
private label: string = 'proffesion :';
private placeholder: string = 'Select profession';
@ViewChild(NgModel) model: NgModel;
constructor(private proffesionService: ProfessionDataService,
@Optional() @Inject(NG_VALIDATORS) validators: Array<any>,
@Optional() @Inject(NG_ASYNC_VALIDATORS) asyncValidators: Array<any>,
) {
super(validators, asyncValidators);
}
ngOnInit() {
this.professionService.getDevelopersProfessions().subscribe(
data => {
this.data = data;
}
);
}
}
ElementBase是與驗證通用ControlValueAccessor:http://blog.rangle.io/angular-2-ngmodel-and-custom-form-components/
所以我的問題是,當我爲孩子創造(developerSearch,buildingSearch)模板與ngModel傳遞的值不爲他們初始化我得到:
EXCEPTION: Uncaught (in promise): Error: Error in ./DeveloperSearchControlComponent class DeveloperSearchControlComponent - inline template:2:33 caused by: Cannot read property 'name' of null
Error: Error in ./DeveloperSearchControlComponent class DeveloperSearchControlComponent - inline template:2:33 caused by: Cannot read property 'name' of null
因爲ngModel的值在開始時爲null。所以我必須在看起來不好的子組件模板中使用* ngFor =「value」。 在模板驗證之前是否有任何解決方案來初始化對象?或者我這樣做是非常錯誤的?
你嘗試了貓王運營商無處不在,你使用的價值?就像''。至少,這將抑制異常。 – mickdev
@mickdev安全導航操作符不能用於'[(ngModel)]';) – Alex
@ AJT_82我從來沒有嘗試過,但在我看來這是可能的。我不明白爲什麼不... – mickdev