我在做什麼錯誤在php中聲明一個對象數組？

Question

這可能太明顯了，但我現在有點腦子死了。

$sizeArr = array({ 
        "name"=>'18"x24"',"wd"=>18,"ht"=>24,"price"=>99.00 
       }, 
       { 
        "name"=>'24"x36"',"wd"=>24,"ht"=>36,"price"=>189.00 
       }); 

我希望它像$sizeArr[0]->name訪問，但是我收到一個錯誤說Unexpected {。

我在做什麼錯？

Answer 1

您不能使用{}來定義PHP中的對象，就像您在JavaScript中所定義的那樣（我假設您熟悉這一點）。

在PHP對象和數組都是array s - 是的，如果你序列化爲JSON，這會產生問題。

所以：

$sizeArr = array(array(
    "name"=>'18"x24"',"wd"=>18,"ht"=>24,"price"=>99.00 
), 
array(
    "name"=>'24"x36"',"wd"=>24,"ht"=>36,"price"=>189.00 
)); 

Answer 2

必須轉換陣列：

$yourArray = array (
    'item1' => 'Apple', 
    'item2' => 'Peach' 
); 

$p = (object) $yourArray; 
print $p->item1; 

多維數組，看看這裏：http://www.richardcastera.com/blog/php-convert-array-to-object-with-stdclass

Answer 3

你不能使用{}這個，但你可以試試這個

(object)是爲轉換array到object

$sizeArr = array(
    (object)array(
     "name"=>'18"x24"',"wd"=>18,"ht"=>24,"price"=>99.00 
    ), 
    (object)array(
     "name"=>'24"x36"',"wd"=>24,"ht"=>36,"price"=>189.00 
    ) 
); 
echo $sizeArr[0]->name; 

$sizeArr結構print_r($sizeArr);輸出

Array 
(
    [0] => stdClass Object 
    (
     [name] => 18"x24" 
     [wd] => 18 
     [ht] => 24 
     [price] => 99 
    ) 

    [1] => stdClass Object 
    (
     [name] => 24"x36" 
     [wd] => 24 
     [ht] => 36 
     [price] => 189 
    ) 

) 

輸出：

18"x24" 

Answer 4

$sizeArr = array(
        (object)array("name"=>'18"x24"',"wd"=>18,"ht"=>24,"price"=>99.00), 
        (object)array("name"=>'24"x36"',"wd"=>24,"ht"=>36,"price"=>189.00) 
        ); 



    $sizeArr[0]->name;