我想創建一個python腳本,它將查找一系列子文件夾並刪除空的shapefile文件。我已經成功創建了將刪除一個文件夾中的空文件的腳本部分,但「Project」文件夾中共有70個文件夾。雖然我可以複製並粘貼69次代碼,但我確定必須讓它查看每個子文件夾併爲每個子文件夾運行代碼。以下是我迄今爲止所擁有的。有任何想法嗎?我對此很新,我只是編輯了一個現有的代碼來實現這一目標。謝謝!如何讓Python查看子文件夾?
import os
# Set the working directory
os.chdir ("C:/Naview/Platypus/Project")
# Get the list of only files in the current directory
file = filter(os.path.isfile, os.listdir('C:/Naview/Platypus/Project'))
# For each file in directory
for shp in file:
# Get only the files that end in ".shp"
if shp.endswith(".shp"):
# Get the size of the ".shp" file.
# NOTE: The ".dbf" file can vary is size whereas
# the shp & shx are always the same when "empty".
size = os.path.getsize(shp)
print "\nChecking " + shp + "'s file size..."
#If the file size is greater than 100 bytes, leave it alone.
if size > 100:
print "File is " + str(size) + " bytes"
print shp + " will NOT be deleted \n"
#If the file size is equal to 100 bytes, delete it.
if size == 100:
# Convert the int output from (size) to a string.
print "File is " + str(size) + " bytes"
# Get the filename without the extention
base = shp[:-4]
# Remove entire shapefile
print "Removing " + base + ".* \n"
if os.path.exists(base + ".shp"):
os.remove(base + ".shp")
if os.path.exists(base + ".shx"):
os.remove(base + ".shx")
if os.path.exists(base + ".dbf"):
os.remove(base + ".dbf")
if os.path.exists(base + ".prj"):
os.remove(base + ".prj")
if os.path.exists(base + ".sbn"):
os.remove(base + ".sbn")
if os.path.exists(base + ".sbx"):
os.remove(base + ".sbx")
if os.path.exists(base + ".shp.xml"):
os.remove(base + ".shp.xml")