2017-05-18 76 views
2

我有這樣的Ajax調用成功時我有沒有顯示仿真模型顯示/隱藏

這裏引導模式是代碼

$(document).ready(function() { 
    $('form').submit(function(e){ 
     var name = $('#name').val(); 
     var email = $('#email').val(); 
     var message = $('#message').val(); 

     var data = 'name=' + name + '&email=' + email + '&message=' + message; 

     $.ajax({ 
     type: "post", 
     url: 'script.php', 
     data: data, 
     success: $(document)ready(function(){ 
     $("#myModal").modal('show'); 
     ) 
     }); 
     e.preventDefault(); // avoid to execute the actual submit of the form. 
    }); 
    }); 

回答

0

有幾個錯誤和語法錯誤的代碼中的

試試這個

$(document).ready(function() { 
    $('form').submit(function(e){ 
     var name = $('#name').val(); 
     var email = $('#email').val(); 
     var message = $('#message').val(); 

     var data = 'name=' + name + '&email=' + email + '&message=' + message; 

     $.ajax({ 
     type: "post", 
     url: 'script.php', 
     data: data, 
     success: $(document).ready(function(){ //missing . before ready 
     $("#myModal").modal("show"); 
     }) // you was missing } here 
     }); 
     e.preventDefault(); // avoid to execute the actual submit of the form. 
    }); 
    }); 
+0

謝謝你洙多 – oolre