如何使動作表按鈕轉到另一個頁面？

Question

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex { 
    if (buttonIndex == 0) { 
     self.label.text = @"Destructive Button Clicked"; 
    } else if (buttonIndex == 1) { 
     self.label.text = @"Other Button 1 Clicked"; 
    } else if (buttonIndex == 2) { 
     self.label.text = @"Other Button 2 Clicked"; 
    } else if (buttonIndex == 3) { 
     self.label.text = @"Cancel Button Clicked"; 
    } 

    /** 
    * OR use the following switch statement 
    * Suggested by Colin =) 
    */ 

    /* 
    switch (buttonIndex) { 
     case 0: 
      self.label.text = @"Destructive Button Clicked"; 
      break; 
     case 1: 
      self.label.text = @"Other Button 1 Clicked";    
      break; 
     case 2: 
      //??????????? 
      self.label.text = @"Other Button 2 Clicked"; <<<<<< WHAT DO I PUT HERE???*** 
      //??????????? 
      break; 
     case 3: 
      self.label.text = @"Cancel Button Clicked"; 
      break; 
    } 
    */ 
} 

我在說self.label等地方放什麼？我需要讓其中一個按鈕進入另一個頁面。換句話說，如果我要說「是」，「我想繼續」，我點擊「繼續」，它會帶我到另一個故事板。

編輯：看看它說：「我該怎麼把這裏」的一部分，這是我想知道的是什麼類型的代碼，這樣我可以做我想要的地方？

Answer 1

你只需要實例化視圖控制器，並使用導航控制器去那個視圖 - 控制

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex 
{ 
    if(buttonIndex == 0) 
    { 
     NewViewController *newview = [self.storyboard instantiateViewControllerWithIdentifier:@"NewView"]; 
     [self.navigationController pushViewController:newview animated:YES]; 
    } 
    else if(buttonIndex==1) 
    { 
     NewViewController1 *newview1 = [self.storyboard instantiateViewControllerWithIdentifier:@"NewView1"]; 
     [self.navigationController pushViewController:newview1 animated:YES]; 
    } 
}