顯示當前工作日和日期

我遇到了一些問題。我希望我在本週顯示所有日期（因爲我寫的是第38周（格里高利））。我擁有的不錯，但它並沒有顯示正確的日子。例如：本週星期一是9月15日，星期日是9月21日。當我設置一週的第一天時，它將它設置爲9月14日星期天。顯示當前工作日和日期

NSDate *currentDate = [NSDate date]; 
NSCalendar *myCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; 

NSDateComponents *currentComps = [myCalendar components:(NSYearCalendarUnit | NSMonthCalendarUnit | NSWeekOfYearCalendarUnit | NSWeekdayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit) fromDate:currentDate]; 
int thisWeeksNumber = currentComps.weekOfYear; 
NSLog(@"1 %d", thisWeeksNumber); //This displays the correct week. 

[currentComps setWeekday:1]; 
NSDate *firstDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:2]; 
NSDate *secondDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:3]; 
NSDate *thirdDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:4]; 
NSDate *fourthDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:5]; 
NSDate *fifthDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:6]; 
NSDate *sixthDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 
[currentComps setWeekday:7]; 
NSDate *seventhDayOfTheWeek = [myCalendar dateFromComponents:currentComps]; 

NSDateFormatter *myDateFormatter = [[NSDateFormatter alloc] init]; 
myDateFormatter.dateFormat = @"yyyy-MM-dd"; 
NSString *firstStr = [myDateFormatter stringFromDate:firstDayOfTheWeek]; 
NSString *secondStr = [myDateFormatter stringFromDate:secondDayOfTheWeek]; 
NSString *thirdStr = [myDateFormatter stringFromDate:thirdDayOfTheWeek]; 
NSString *fourthStr = [myDateFormatter stringFromDate:fourthDayOfTheWeek]; 
NSString *fifthStr = [myDateFormatter stringFromDate:fifthDayOfTheWeek]; 
NSString *sixthStr = [myDateFormatter stringFromDate:sixthDayOfTheWeek]; 
NSString *seventhStr = [myDateFormatter stringFromDate:seventhDayOfTheWeek]; 

NSLog(@"\n %@ \n %@ \n %@ \n %@ \n %@ \n %@ \n %@", firstStr, secondStr, thirdStr, fourthStr, fifthStr, sixthStr, seventhStr);

這應該顯示九月15日至九月21，但它顯示九月14日（星期日）至九月21日（星期六）。

在此先感謝！

來源

2014-09-20 Dridia

如果您查看文檔它不正是它應該做的：

https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSDateComponents_Class/Reference/Reference.html#//apple_ref/occ/instm/NSDateComponents/setWeekday：

當你調用setWeekDay - 1表示星期天，所以如果你需要開始與星期一你首先應該聯繫setWeekDay:2

更新：

至於第一個我會建議實施類似的東西之後會和讓所有連續的天（插入此函數成你的代碼）：

- (NSDate*)dateByAddingDays:(NSInteger)days toDate:(NSDate *)date 
{ 
    NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; 
    NSDateComponents *comps = [[NSDateComponents alloc] init]; 
    comps.day = days; 

    return [calendar dateByAddingComponents: comps toDate: date options: 0]; 
}

並使用此功能從你開始你的星期的那天開始加1-6。具有以下

[currentComps setWeekday:2]; 
NSDate *secondDayOfTheWeek = [myCalendar dateFromComponents:currentComps];

：基本上替換所有第二天等代碼

NSDate *secondDayOfTheWeek = [self dateByAddingDays:1 toDate:firstDayOfTheWeek]; 
NSDate *thirdOfTheWeek = [self dateByAddingDays:2 toDate:firstDayOfTheWeek]; 
...

來源

2014-09-20 15:45:43 sha

是的，我已經試過了。但是，我如何獲得9月21日的星期天？ Cuz'一週不會以星期天開始。 – Dridia 2014-09-20 16:18:44

@Dridia：檢查更新的答案。 – sha 2014-09-20 16:32:10

我不知道我應該如何在我的代碼中實現這一點。 – Dridia 2014-09-20 16:35:57

顯示當前工作日和日期

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