回到代碼塊的開始

Question

我對C++相當陌生，但是我正在做一個簡單的程序，我將如何返回到代碼的開頭，同時還記得輸入的內容。例如說我按了1而不是輸入名字，我將如何回到主要部分，它會詢問你想要什麼。感謝您的時間我很感激

#include <iostream> 
#include <string> 
#include <iomanip> 

using namespace std; 

int main(int argc, char *argv[]) 
{ 
char name[25]; 
char address[25]; 
char city[25]; 
char state[25]; 
char zip[25]; 
char phone[25]; 
int reply; 

cout <<"Press 1 to enter the name"<<endl; 
cout <<"Press 2 to enter the address"<<endl; 
cout <<"Press 3 to enter the city"<<endl; 
cout <<"Press 4 to enter the state"<<endl; 
cout <<"Press 5 to enter the zip"<<endl; 
cout <<"Press 6 to enter the phone"<<endl; 
cin >>reply; 
if (reply = 'one') 
{ cout << " Enter the name" << endl; 
    cin >> name; 
    cin.ignore(80, '\n');} 
else if (reply = 'two') 
    {cout << " Enter the address" << endl; 
    cin >> address; 
    cin.ignore(80, '\n');} 
else if (reply = 'three') 
    {cout << " Enter the city" << endl; 
    cin >> city; 
    cin.ignore(80, '\n');} 
else if (reply = 'four') 
    {cout << " Enter the state" << endl; 
    cin >> state; 
    cin.ignore(80, '\n');} 
else if (reply = 'five') 
    { cout << " Enter the zip code " << endl; 
    cin >> zip; 
    cin.ignore(80, '\n');} 
else if (reply = 'six') 
    { cout << " Enter the phone number " << endl; 
    cin >> phone; 
    cin.ignore(80, '\n');} 
else 
{cout << " done";} 





system ("PAUSE"); 
return EXIT_SUCCESS; 

}

Answer 1

請注意，這裏的條件：

int reply; 
cin >>reply; 
if (reply = 'one') 
    ... 

實際意思是：

if (reply == 1) 

文字放在''之間請參閱單個char字符串，你應該使用""和數字文字，如int，只需使用數字。您還應該添加一個選項來停止程序：

cout << "Press 1 to enter the name" << endl; 
cout << "Press 2 to enter the address" << endl; 
... 
cout << "Press 0 to stop" << endl;    // <-- something like this 

並用循環包裝這段代碼。另外請注意，變量不需要在函數的開頭聲明。

---

它可能看起來方式如下：

// print choices (press *** to ...) 
int reply; 
while (cin >> reply) { 
    if (reply == 0) 
     break; 
    // some code... 
    // print choices 
} 

Answer 2

你想要的是一個循環！不要相信GOTO和LABEL的謊言！使用結構合理的代碼，您可以始終避免使用這些維護噩夢。考慮以下幾點：

bool doContinue = true; 
int userNumber = 0; 

while(doContinue) 
{ 
    int temp = 0; 

    cout << "What's your next favorite number?" 
    cin >> temp; 

    userNumber += temp; 

    cout << "The sum of your favorite numbers is " << userNumber << endl; 

    cout << "Continue?" << endl; 
    cin >> temp; 

    doContinue = temp != 0; 
} 

這個想法是讓循環之外的變量保存在循環中收集的數據。這樣您就可以重複邏輯而不必重複代碼。這個例子只是從用戶輸入中檢索數字並對它們進行求和，但它顯示了基本循環的想法。此外，循環必須具有退出條件（在這種情況下爲doContinue == false）。