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我已經仿照兩個類具有多對多的關係:用戶與對話,當我使用他們,我不能創建這兩個類之間的鏈接:如何創建相關的記錄與學說PHP
class User extends Doctrine_Record
{
public function setTableDefinition() {
$this->hasColumn('udid', 'string', 255);
$this->hasColumn('nb_requetes', 'integer', 255);
}
public function setUp() {
$this->actAs('Timestampable');
$this->hasMany('Conversation as Conversations',
array('local'=> 'user_id',
foreign'=> 'conversation_id',
'refClass' => 'UserConversation'));
}
}
而且
class Conversation extends Doctrine_Record
{
public function setTableDefinition() {
$this->setTableName('conversations');
$this->hasColumn('initiator_id', 'integer', 20);
$this->hasColumn('responder_id', 'integer', 20);
}
public function setUp() {
$this->actAs('Timestampable');
$this->hasMany('User as Users',
array('local' => 'conversation_id',
'foreign' => 'user_id',
'refClass' => 'UserConversation'));
}
}
我試圖做類似的東西,使用它:
$user = new User();
$user->save();
$conversation = new Conversation();
$conversation->users[] = $user;
$conversation->save();
但它不是工作,我的聯結表「UserConversation」保持空白......我是否正確地採取行動?
謝謝您的回答,
馬丁
是'$ conversation-> users [0] = $ user;加工? – DrColossos 2010-10-18 09:09:13