5
A
回答
2
你必須創建爲每個表的簡單模型關係,然後你可以
[rails3] > rails generate scaffold_controller Club name:string exclusive:boolean
create app/controllers/clubs_controller.rb
invoke erb
create app/views/clubs
create app/views/clubs/index.html.erb
create app/views/clubs/edit.html.erb
create app/views/clubs/show.html.erb
create app/views/clubs/new.html.erb
create app/views/clubs/_form.html.erb
create app/views/layouts/clubs.html.erb
invoke test_unit
create test/functional/clubs_controller_test.rb
或者你可以嘗試active_admin寶石
ActiveAdmin - https://github.com/gregbell/active_admin
rails generate active_admin:resource [MyModelName]
RailsAdmin也夠https://github.com/sferik/rails_admin
你應該爲你的模型指定至少2分的規則,如果它不使用好軌道約定。 例
class Article < ActiveRecord::Base
self.table_name "tbl_articles"
self.primary_key "art_id"
end
0
0
這是你如何能做到這一點 -
嘗試:
rails g scaffold myscaffold
這將生成文件:
invoke active_record
create db/migrate/20130124100759_create_myscaffolds.rb
create app/models/myscaffold.rb
invoke test_unit
create test/unit/myscaffold_test.rb
create test/fixtures/myscaffolds.yml
route resources :myscaffolds
invoke scaffold_controller
create app/controllers/myscaffolds_controller.rb
invoke erb
create app/views/myscaffolds
create app/views/myscaffolds/index.html.erb
create app/views/myscaffolds/edit.html.erb
create app/views/myscaffolds/show.html.erb
create app/views/myscaffolds/new.html.erb
create app/views/myscaffolds/_form.html.erb
invoke test_unit
create test/functional/myscaffolds_controller_test.rb
invoke helper
create app/helpers/myscaffolds_helper.rb
invoke test_unit
create test/unit/helpers/myscaffolds_helper_test.rb
invoke assets
invoke coffee
create app/assets/javascripts/myscaffolds.js.coffee
invoke scss
create app/assets/stylesheets/myscaffolds.css.scss
invoke scss
identical app/assets/stylesheets/scaffolds.css.scss
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只是好奇,如果你正在使用rails''紅寶石那你爲什麼想從數據庫中創建,爲什麼不從'rails命令line'? –
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